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Strike441 [17]
3 years ago
5

What is the product of 3a +5 and 2a^2+ 4a - 2?

Mathematics
1 answer:
love history [14]3 years ago
8 0

Answer:

(3a + 5)(2a^2 + 4a - 2)

=3a(2a^2 + 4a - 2) + 5(2a^2 + 4a - 2)

=6a^3 + 12a^2 - 6a + 10a^2 + 20a - 10

=6a^3 + 22a^2 + 14a - 10

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Find the radius of convergence, r, of the series. ? n2xn 7 · 14 · 21 · ? · (7n) n = 1
defon
I'm guessing the series is supposed to be

\displaystyle\sum_{n=1}^\infty\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}

By the ratio test, the series converges if the following limit is less than 1.

\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7\cdot14\cdot21\cdot\cdots\cdot(7n)\cdot(7(n+1))}}{\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}}\right|

The first n terms in the numerator's denominator cancel with the denominator's denominator:

\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7(n+1)}}{n^2x^n}\right|

|x^n| also cancels out and the remaining factor of |x| can be pulled out of the limit (as it doesn't depend on n).

\displaystyle|x|\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2}{7(n+1)}}{n^2}\right|=|x|\lim_{n\to\infty}\frac{|n+1|}{7n^2}=0

which means the series converges everywhere (independently of x), and so the radius of convergence is infinite.
3 0
4 years ago
Select two statements that are true about the equation y+4=-8(x-2)
bezimeni [28]

Answer:

Step-by-step explanation:

y + 4 = -8(x - 2)

I dont know the statements that u have but maybe I can guess one...or two

slope = -8

points used were : (2,-4)

y + 4 = -8(x - 2)

y + 4 = -8x + 16

y = -8x + 16 - 4

y = -8x + 12 ............slope intercept form

8x + y = 12 .......standard form

x intercept = (3/2,0)

y intercept = (0,12)

any of that answer ur question ?

5 0
3 years ago
Read 2 more answers
The question is in the picture please help
ahrayia [7]

Answer:

Claim 2

Step-by-step explanation:

The Inscribed Angle Theorem* tells you ...

... ∠RPQ = 1/2·∠ROQ

The multiplication property of equality tells you that multiplying both sides of this equation by 2 does not change the equality relationship.

... 2·∠RPQ = ∠ROQ

The symmetric property of equality says you can rearrange this to ...

... ∠ROQ = 2·∠RPQ . . . . the measure of ∠ROQ is twice the measure of ∠RPQ

_____

* You can prove the Inscribed Angle Theorem by drawing diameter POX and considering the relationship of angles XOQ and OPQ. The same consideration should be applied to angles XOR and OPR. In each case, you find the former is twice the latter, so the sum of angles XOR and XOQ will be twice the sum of angles OPR and OPQ. That is, angle ROQ is twice angle RPQ.

You can get to the required relationship by considering the sum of angles in a triangle and the sum of linear angles. As a shortcut, you can use the fact that an external angle is the sum of opposite internal angles of a triangle. Of course, triangles OPQ and OPR are both isosceles.

4 0
3 years ago
13.24503311258278 Round to the nearest tenth as needed
Ksenya-84 [330]

The number provided rounded to the nearest tenth is 13.2.

Because the number in the hundreds place is a 4, we round down and keep the tenth at 2.

7 0
3 years ago
Select the correct answer. Find the solution(s) for x in the equation below.<br> x2-9x+20=0
trasher [3.6K]

Step-by-step explanation:

Given

x² - 9x + 20 = 0

x² - ( 4 + 5) x + 20 = 0

x² - 4x - 5x + 20 = 0

x ( x - 4 ) - 5 (x - 4 ) = 0

(x - 4 ) ( x - 5 ) = 0

Either

x - 4 =0

x = 4

or

x - 5 =0

x = 5

x = 4 and 5

Hope it will help :)

.)

8 0
3 years ago
Read 2 more answers
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