Question

I have $28.65 worth of coins. The coins are in denominations of 1, 5, 10, 25, 50 cents and $1.

Answer 1

Answer:

• 15 equal number of coins of each denomination
• 90 coins are there in all together.

Step-by-step explanation:

make all the currency to cents

[ let x be the equal number of coins in each denomination ]

x (1+5+10+25+50+100) = 2865

x (191) = 2865

x = 2865 ÷ 191

x = 15

There are 15 equal number of coins of each denomination.

There are 6 types of coins - 1c, 5c, 10c, 25c, 50c, 100c

So there are [ 6 * 15 ] → 90 coins in all together.

Answer 2

Answer:

90 coins

Step-by-step explanation:

let x = number of coins of each denomination:

$0.01x+0.05x+0.1x+0.25x+0.5x+x=28.65$

$\implies 1.91x=28.65$

$\implies x=15$

So there are 15 coins of EACH denomination.

As there are 6 different types of coins, there are 6 x 15 = 90 coins in total