The two quadrilaterals are given similar .
In any similar figure sides are in proportion.The second largest side of quadrilateral ABCD is 16 ft .Let the second longest side of quadrilateral EFGH be x ft. These sides will be in proportion to each other .
The second shortest side of quadrilateral EFGH that is GF will be proportional to the third longest side of quadrilateral ABCD that is BC
We can form a proportion with the proportional sides:
![\frac{16}{x} =\frac{12}{18}](https://tex.z-dn.net/?f=%20%5Cfrac%7B16%7D%7Bx%7D%20%3D%5Cfrac%7B12%7D%7B18%7D%20%20)
To solve for x we cross multiply
12x=(16)(18)
12x=288
Dividing both sides by 12 we get
x=24.
The second longest side of quadrilateral EFGH is 24 ft.
Answer:
f(x) = 4x
Step-by-step explanation:
-2 x 4 = -8
-1 x 4 = -4
0 x 4 = 0
1 x 4 = 4
Okay so you need to get the y by itself
2x - 4y = 20
subtract the 2x over
-4y = -2x + 20
divide everything by -4
y = 1/2x - 5 <------- this is your answer
Answer:
1432
Step-by-step explanation:
a = by/2. then add all areas together to get final answer.
The complete question in the attached figure
we know that
When we know <span>two sides and the included angle the formula for calculate the area is
</span>Area=(1/2)*a*b*sin C
in this problem
let
a=20
b=12
C=68°
Area=(1/2)*20*12*sin 68°------> Area=111.26 units²-----> Area=111.3 units²
the answer is111.3 units²