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3 years ago

1. Find the sum of the measures of the interior angles of a convex hexagon.

Mathematics

2 answers:

butalik [34]3 years ago

7 0

Answer:

could you include a pic please?

Grace [21]3 years ago

6 0

Can you please include a picture

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A stereo system cost $275. It was on sale for 15% off. The sales person receives a 2% commission. How much of a commission do th

kkurt [141]

The price of the stereo on sale
is
275 - ( 275x15% ) =
233.75

the comission is 233.75 x 2 % =
233.75 x 2/100 = 4.675

8 0

3 years ago

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What is the rate of change of the function?

olga_2 [115]

Answer:

Step-by-step explanation:

the rate of change of the function, or the slope is 3 because to get to one point from the other point in the line, you would have to go up 3 and over 1 (3/1) or just 3.

Hope this helps

5 0

3 years ago

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Averi was trying to factor 4x^2+20x-164x

loris [4]

Answer:

the width is 24

Step-by-step explanation:

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2 years ago

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How much of an alloy with 30% copper must be added to 25 pounds of a second alloy that is 20% copper to create a 27% alloy? 33.8

yuradex [85]

Answer:

58.33 lbs.

Step-by-step explanation:

There are already 25 lbs of alloy of copper

Of this 25 lbs, 20% is pure i.e. copper content = 25(0.5) = 5lbs.

Now available is

Copper Other metals

5 lbs 20 lbs

Let x lb of 30% copper is added.

Then new alloy will have 5+0.3x lb copper in total of 25+x lbs

Percentage pure = $\frac{5+0.3x}{25+x} =27%$

Simplify to get

$\frac{5+0.3x}{25+x} =\frac{27}{100} \\\\Cross multiply:\\27(25+x) =100(5+0.3x)\\500+30x =675 +27x\\3x = 175\\x = 175/3 = 58.33 lbs$

Hence answer is 58.33 lbs should be added.

8 0

3 years ago

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Exercise 12.1.1: Coin flips and events. About A coin is flipped four times. For each of the events described below, express the

butalik [34]

Answer:

a $Pr = 0.25$

b $Pr = 0.50$

c $Pr = 0.1875$

Step-by-step explanation:

Given

$n = 4$ --- number of times

$r = 2$ --- faces of a coin

First, is to determine the sample size.

This is calculated as:

$Size =r^n$

$Size =2^4$

$Size =16$

Solving (a): First and last slip is head

This event is represented as:

$E=\{HHHH, HHTH, HTHH, HTTH\}$

The probability is calculated as:

$Pr = \frac{n(E)}{Size}$

$Pr = \frac{4}{16}$

$Pr = 0.25$

b) At least 2 consecutive flips that is heads.

This event is represented as:

$E=\{HHHH,HHHT,HHTH,HHTT,THHH,THHT,HTHH,TTHH\}$

The probability is calculated as:

$Pr = \frac{n(E)}{Size}$

$Pr = \frac{8}{16}$

$Pr = 0.50$

c) First is tail and at least 2 consecutive flips is head.

This event is represented as:

$E=\{THHH,THHT,TTHH\}$

The probability is calculated as:

$Pr = \frac{n(E)}{Size}$

$Pr = \frac{3}{16}$

$Pr = 0.1875$

8 0

2 years ago