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Rom4ik [11]
3 years ago
10

1. Find the sum of the measures of the interior angles of a convex hexagon.

Mathematics
2 answers:
butalik [34]3 years ago
7 0

Answer:

could you include a pic please?

Grace [21]3 years ago
6 0
Can you please include a picture
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Given the equation, C = P + (P)(T), what is the final cost of a cell phone priced at $20.00 with a tax rate of 5%?
sergij07 [2.7K]

Answer: Answer is $21

Step-by-step explanation:

Using the equation C = P + (P)(T)

where P= $20

T= 5%; 5/100 = 0.05

Substitute the figures in the equation,

$20 + $20 (0.05)

Apply BODMAS and open bracket first

$20 + $1

= $21

6 0
3 years ago
In your own words, summarize how the Jacksonian Era was characterized?
Neporo4naja [7]

The Jacksonian Era was characterized by the idea that every citizen was equally important and that all should participate actively in government. The old friends whom Jackson consulted instead of his regular cabinet were called the "kitchen cabinet."

5 0
3 years ago
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Which fractions have a LCD of 30? A. 3/4 1/7 16 B.2/3 1/5 1/15 C. 2/15 1/4 1/3 D. 2/3 1/5 1/6
wolverine [178]

Answer:

1/5, 1/6 and 1/15

Step-by-step explanation:

Multiples of 15 are 30, 45, 60, 75, 90. Now, when you look at the list of multiples, you can see that 30 is the smallest number that appears in each list. Therefore, the least common denominator of 1/5, 1/6, and 1/15 is 30.

6 0
3 years ago
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847.875 round to the nearest tenth
guajiro [1.7K]

Answer:

847.9

Step-by-step explanation:

6 0
3 years ago
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(Photo attached) Trig question. Please explain and thanks in advance! :)
nirvana33 [79]

Answer:

  0.2036

Step-by-step explanation:

u = arcsin(0.391) ≈ 23.016737°

tan(u/2) = tan(11.508368°)

tan(u/2) ≈ 0.2036

__

You can also use the trig identity ...

  tan(α/2) = sin(α)/(1+cos(α))

and you can find cos(u) as cos(arcsin(0.391)) ≈ 0.920391

or using the trig identity ...

  cos(α) = √(1 -sin²(α)) = √(1 -.152881) = √.847119

Then ...

  tan(u/2) = 0.391/(1 +√0.847119)

  tan(u/2) ≈ 0.2036

__

<em>Comment on the solution</em>

These problems are probably intended to have you think about and use the trig half-angle and double-angle formulas. Since you need a calculator anyway for the roots and the division, it makes a certain amount of sense to use it for inverse trig functions. Finding the angle and the appropriate function of it is a lot easier than messing with trig identities, IMO.

6 0
3 years ago
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