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Lubov Fominskaja [6]

3 years ago

11

PLEASE HELP I NEED TO RAISE MY GRADE PLEASE

1 answer:

777dan777 [17]3 years ago

5 0

Answer:

AC, AB. BC

Step-by-step explanation:

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Which of the following are solutions to the equation below?

sladkih [1.3K]

Answer:

$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

$x=3,\:x=-\frac{1}{2}$

Step-by-step explanation:

considering the equation

$2x^2\:-\:4x\:-\:3\:=\:x$

solving

$2x^2\:-\:4x\:-\:3\:=\:x$

$2x^2-4x-3-x=x-x$

$2x^2-5x-3=0$

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=2,\:b=-5,\:c=-3:\quad x_{1,\:2}=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

solving

$x=\frac{-\left(-5\right)+\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

$x=\frac{5+\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}$

$x=\frac{5+\sqrt{49}}{2\cdot \:2}$

$x=\frac{5+7}{4}$

$x=3$

also solving

$x=\frac{-\left(-5\right)-\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

$x=\frac{5-\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}$

$x=\frac{5-\sqrt{49}}{4}$

$x=-\frac{2}{4}$

$x=-\frac{1}{2}$

Therefore,

$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

$x=3,\:x=-\frac{1}{2}$

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4 years ago

Heidi buys shirts for $20 and resells for $24. What is the percentage of Heidi's markup? Plz help me!!

Vadim26 [7]

20% because 4 dollars is 1/5 of 20

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4 years ago

Which of the following properties does not work for addition?

Simora [160]

Answer:

I believe it is Identity

3 0

3 years ago

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Gareth buys two oranges. He pays with a £1 coin and gets 52p change. Work out the cost of one orange.

zalisa [80]

Answer:

24p

Step-by-step explanation:

£1 - £0.52 = £0.48 ← cost of 2 oranges

cost of 1 orange = £0.48 ÷ 2 = £0.24

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2 years ago

What are TWO different ways you know when you are finished dividing?

vfiekz [6]

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