Question

Write x^2 + 4x +5 in the form of (x + a)^2 + b where a and b are integers

Answer 1

Answer:

$(x+2)^2 + 1 \ , \ where \ a = 2 \ , \ b = 1$

Step-by-step explanation:

$(x + 2)^2 = x^2 + 4x + 4\\\\(x+2)^2 + 1 = x^2 + 4x + 5$

$Therefore,$

                $x^2 + 4x + 5 = (x+2)^2 + 1$