Answer:
the answer is 1295
Step-by-step explanation:
Answer:
When increasing the radius 3 times the volume increases 9 times and when it is reduced to a third the volume decreases 9 times
Step-by-step explanation:
We have that the formula for the volume of a cone is:
Vc = pi * (r ^ 2) * h
We first calculate the original volume, where the radius is 2 and the height is 9, replacing:
Vc = 3.14 * (2 ^ 2) * 9
Vc = 113.04
Now if the radius is tripled it would be: 2 * 3 = 6, the radius would be 6, replacing:
Vc = 3.14 * (6 ^ 2) * 9
Vc = 1017.36
If we compare:
1017.36 / 113.04 = 9
This means that when the radius is tripled, the volume increases 9 times.
When if re reduces to a third the radius would be: 2/3, replacing:
Vc = 3.14 * ((2/3) ^ 2) * 9
Vc = 12.56
113.04 / 12.56 = 9
Which means that by reducing it to a third the volume becomes 9 times smaller.
The answer is.. 23 and 16
Hope this helps!!
Answer:
If we assume a temperature of 20ºc and the blood interfacial surface tension is similar to water interfacial surface tension, the diameter of the capillary tube should be 0.933mm.
Step-by-step explanation:
The Jurin law describes the height a fluid can reach in a capillary tube. This law can be written as:
where γ is the interfacial surface tension, θ is the contact angle with the fluid, ρ is the fluid density, g is the gravity acceleration and r is the tube radius.
If we assume that the interfacial surface tension of blood and water are almost the same, γ=0,0728 N/m at 20ºc. Therefore the diameter of the tube will be:
2x⁴+17x²+8
Let X = x² →→(x = + or -√X )
The quadratic becomes : 2.X² + 17.X + 8. Now solve for X:
X' = [-b+√(b²-4ac)]/2a and X" = [-b-√(b²-4ac)]/2a
Plug I the values of a, b and c and you will find;
X' = -1/2 and X" = - 8
Since X = √x → →X' = √( -1/2) [imaginary roots]
and X" = √-8 →→ X" = 2√-2 [imaginary roots]
Then:
1st ROOT: X' = - √1/2.i
2nd ROOT: X" = + √1/2.i
3rd ROOT: X" = + 2√2.i
4th ROOT: X" = - 2√2.i
