Question

Select the two values of x that are roots of this equation. X2 + 2x - 5 = 0

Answer 1

Answer:

$x=-1+\sqrt{6 }$

$x=-1-\sqrt{6 }$

Step-by-step explanation:

$x=\frac{-b±\sqrt{b^{2}-4ac } }{2a}$

Ignore the A before the ±. It wouldn't let me type it correctly.

x² + 2x - 5 = 0

a = 1

b = 2

c = - 5

$x=\frac{-2±\sqrt{2^{2}-4((1)(-5)) } }{2(1)}$

$x=\frac{-2±\sqrt{4-4((1)(-5)) } }{2(1)}$

$x=\frac{-2±\sqrt{4+20 } }{2(1)}$

$x=\frac{-2±\sqrt{24 } }{2}$

$x=\frac{-2±\sqrt{(2)(12) } }{2}$

$x=\frac{-2±\sqrt{(2)(2)(6) } }{2}$

$x=\frac{-2±\sqrt{(2)(2)(2)(3) } }{2}$

$x=\frac{-2±(\sqrt{2} )(\sqrt{2})(\sqrt{(2)(3) )} }{2}$

$x=\frac{-2±2\sqrt{6 } }{2}$

Two separate equations

$x=\frac{-2+2\sqrt{6 } }{2}$

$x=\frac{-2-2\sqrt{6 } }{2}$

$x=-1+\sqrt{6 }$

$x=-1-\sqrt{6 }$