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3 years ago

I need help with these question! Please do step by step-

Mathematics

1 answer:

trapecia [35]3 years ago

3 0

Answer:

There are 47 Borogroves and 35 Mome raths

Step-by-step explanation:

Here, given the number of legs, we want to find the number of each type of animals

Let the number of borogoves be b and the number of mome raths be m

From the question, there are 82 creatures;

Thus;

m + b = 82 ••••••••(i)

the total number of legs by b borogroves will be b * 2 = 2b

the total number of legs by m mome raths will be m * 4 = 4m

the sum of all legs is 234

2b + 4m = 234 •••••••••(ii)

From equation 1, m = 82-b

Substitute this into equation ii

2b + 4(82-b) = 234

2b + 328 - 4b = 234

4b-2b = 328-234

2b = 94

b = 94/2

b = 47

Recall;

m + b = 82

m + 47 = 82

m = 82-47

m = 35

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sergeinik [125]

Answer:

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Step-by-step explanation:

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2 years ago

Use the rules for multiplication by powers of 10 to calculate 3 x 100

Yakvenalex [24]

300

because 3 x 1 = 3 +00 = 300... make sense?

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2 years ago

If the original quantity is 10 and the new quantity is 6, what is percent increase

Ad libitum [116K]

Answer:

Using the percentage difference formula you can find the percentage decrease.

SO its

100(new-old/new)

So we solve

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2 years ago

The image of (-9,-4) after a reflection over the y-axis?

lidiya [134]

Answer:

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Step-by-step explanation:

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2 years ago

At a cell phone assembly plant, 77% of the cell phone keypads pass inspection. A random sample of 111 keypads is analyzed. Find

Serggg [28]

Answer:

The probability that the proportion of passed keypads is between 0.72 and 0.80 is 0.6677.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

$\mu_{\hat p}=p$

The standard deviation of this sampling distribution of sample proportion is:

$\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}$

Let p = the proportion of keypads that pass inspection at a cell phone assembly plant.

The probability that a randomly selected cell phone keypad passes the inspection is, p = 0.77.

A random sample of n = 111 keypads is analyzed.

Then the sampling distribution of $\hat p$ is:

$\hat p\sim N(p,\ \sqrt{\frac{p(1-p)}{n}})\\\Rightarrow \hat p\sim N (0.77, 0.04)$

Compute the probability that the proportion of passed keypads is between 0.72 and 0.80 as follows:

$P(0.72$

$=P(-1.25$

Thus, the probability that the proportion of passed keypads is between 0.72 and 0.80 is 0.6677.

8 0

3 years ago