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Nimfa-mama [501]
3 years ago
5

Divide by 2 digit DIVISORS (help me with 5-8 questions pls)

Mathematics
2 answers:
poizon [28]3 years ago
4 0

5. 301.2916667

6. 123.4651163

7. 102

8.  20.35185185

hope this helps

mark brainliest please it would help alot

:)

IRINA_888 [86]3 years ago
3 0
5. 301.291667
6. 123.465116
7. 102
8. 20.3518519
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What is 21/49 sinple
NikAS [45]
21/49 in simplist from would be 3/7.
Your answer is <em>3/7</em>
6 0
3 years ago
Read 2 more answers
How do you round 788.44-225.6? really need help:)
Igoryamba

Answer:

532.8

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
D(x)=(x^2-12x+20)/(3x)
krok68 [10]

Answers:

Vertical asymptote: x = 0

Horizontal asymptote: None

Slant asymptote: (1/3)x - 4

<u>Explanation:</u>

d(x) = \frac{x^{2}-12x+20}{3x}

      = \frac{(x-2)(x - 10)}{3x}

Discontinuities: (terms that cancel out from numerator and denominator):

Nothing cancels so there are NO discontinuities.

Vertical asymptote (denominator cannot equal zero):

3x ≠ 0  

<u>÷3</u>   <u>÷3 </u>

x ≠ 0

So asymptote is to be drawn at x = 0

Horizontal asymptote (evaluate degree of numerator and denominator):

degree of numerator (2) > degree of denominator (1)

so there is NO horizontal asymptote but slant (oblique) must be calculated.

Slant (Oblique) Asymptote (divide numerator by denominator):

  •        <u>(1/3)x - 4    </u>
  •    3x)    x² - 12x + 20
  •             <u>x²        </u>
  •                  -12x
  •                  <u>-12x         </u>
  •                             20 (stop! because there is no "x")

So, slant asymptote is to be drawn at (1/3)x - 4



6 0
3 years ago
Find y'' if y= 9csc x
sineoko [7]

Answer:

y" = csc(x)[9cot²(x) - csc²(x)]

Step-by-step explanation:

Step 1: Define

y = 9csc(x)

Step 2: Find 1st derivative

y' = -9csc(x)cot(x)

Step 3: Find 2nd derivative

y" = 9csc(x)cot(x)cot(x) + -csc(x)csc²(x)

y" = 9csc(x)cot²(x) - csc³(x)

y" = csc(x)[9cot²(x) - csc²(x)]

4 0
3 years ago
What is the solution to the quadratic equation 8m^2+7m-15=-7 ?
Aleks04 [339]
Make equal to zero
add7 both sides
8m^2+7m-8=0
quadratic fomrula

if you have
ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}

8m^2+7m-8=0
a=8
b=7
c=-8

x=\frac{-7+/- \sqrt{7^{2}-4(8)(-8)} }{2(8)}
x=\frac{-7+/- \sqrt{49+256} }{16}
x=\frac{-7+/- \sqrt{305} }{16}

x=\frac{-7+ \sqrt{305} }{16} or x=\frac{-7- \sqrt{305} }{16}

aprox
x=-1.52902 or 0.654016


4 0
3 years ago
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