Answer :
<h3>
<u>
=1048576 ways </u>
a student can answer the questions on the test if the student answers every question.</h3>
Step-by-step explanation:
Given that a multiple-choice test contains 10 questions and there are 4 possible answers for each question.
∴ Answers=4 options for each question.
<h3>
To find how many ways a student can answer the given questions on the test if the student answers every question :</h3>
Solving this by product rule
Product rule :
<u>If one event can occur in m ways and a second event occur in n ways, the number of ways of two events can occur in sequence is then m.n</u>
From the given the event of choosing the answer of each question having 4 options is given by
The 1st event of picking the answer of the 1st question=4 ,
2nd event of picking the answer of the 2nd question=4 ,
3rd event of picking the answer of the 3rd question=4
,....,
10th event of picking the answer of the 10th question=4.
It can be written as by using the product rule
<h3>∴ there are 1048576 ways a student can answer the questions on the test if the student answers every question.</h3>
The probability of an event that has two possible outcomes is 1/2
<h3>What is Probability?</h3>
This refers to the likelihood of an event occurring and this can be found by calculating using a mathematical model.
It should be noted that your question is incomplete so I gave you a general overview to help you get a better understanding of the concept.
Read more about probability here:
brainly.com/question/24756209
#SPJ1
Answer:
b=20.431
Step-by-step explanation:
you just add 6.11 to both sides. on the left side the -6.11 and +6.11 cancel out and on the right side you will just add 6.11 to 14.321. when you add 14.321 and 6.11 you get 20.431. therefore, b=20.431
Answer:
gradient is 8 and y intercept is 0
Step-by-step explanation:
y=mc+b
take one pair of corridants:
8=1m+b
m=8 (change in y values/changes in x values)
8=1x8+b
do the equation
y=0
Have a nice day!!!!!!!!! :-)
<u>KA</u>
Amber can make a possible number of 12 different teams
