Let's solve your equation step-by-step.
Question 1: −2(6−2x) =4(−3+x)
Step 1: Simplify both sides of the equation.
−2(6−2x) =4(−3+x)
(−2) (6) +(−2) (−2x) =(4)(−3)+(4)(x)(Distribute)
−12+4x=−12+4x
4x−12=4x−12
Step 2: Subtract 4x from both sides.
4x−12−4x=4x−12−4x
−12=−12
Step 3: Add 12 to both sides.
−12+12=−12+12
0=0
Answer: All real numbers are solutions.
Question 2:
Let's
solve your equation step-by-step.
5−1(2x+3)
=−2(4+x)
Step 1:
Simplify both sides of the equation.
5−1(2x+3)
=−2(4+x)
5+(−1)
(2x) +(−1) (3) =(−2) (4)+(−2)(x)(Distribute)
5+−2x+−3=−8+−2x
(−2x)
+(5+−3) =−2x−8(Combine Like Terms)
−2x+2=−2x−8
−2x+2=−2x−8
Step 2:
Add 2x to both sides.
−2x+2+2x=−2x−8+2x
2=−8
Step 3:
Subtract 2 from both sides.
2−2=−8−2
0=−10
Answer: There are no solutions.
Answer:
f(0,0)=ln19
Step-by-step explanation:
is given as continuous function, so there exist
and it is equal to f(0,0).
Put x=rcosA annd y=rsinA

we know that
, so we have that


So f(0,0)=ln19.
(a) Calculate the vertical distance between the eagle and the seahorse.
Answer a: 11.38 meters is the vertical distance between them.
(b) Describe Adrian's position from the sea level.
Answer b: Adrian is 1.13m below the sea level.
Step-by-step explanation:
(a) Since sea level is the origin of coordinates. distances above sea level are positive and distances below sea level are negative. The distance between two points is the difference between them.
The vertical distance between the eagle and the seahorse is the difference between their positions:
Distance = 4.56m - (-6.82m) = 4.56m + 6.82m = 11.38 meters
Answer a) 11.38 meters is the vertical distance between them.
(b) Adrian's position is in the middle of the distance between the eagle and the seahorse:
Middle = 11.38m/2 = 5.69m
Since 5.69m is more than 4.56m above the sea level, then Adrian is below the sea level:
4.56m - 5.69m = -1.13m
Answer b: Adrian is 1.13m below the sea level.
<h2><em>Spymore</em></h2>
My boiii, tiger algebra helped me out a little on this one, I got 7c * sqrt(5)
Answer:
C.
Step-by-step explanation:
