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3 years ago

10

PLZ HELP!!! its due tomorrow

2 answers:

Feliz [49]3 years ago

6 0

3×5×7×4=420

Answer: 420 outfits

3241004551 [841]3 years ago

5 0

Answer:add 3+5+7

Step-by-step explanation:

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If you have a cubic polynomial of the form y = ax^3 + bx^2 + cx + d and lets say it passes through the points (2,28), (-1, -5),

nikklg [1K]

Step-by-step explanation:

<u>Step 1: Solve using the first point</u>

<em>(2, 28)</em>

$28 = a(2)^3 + b(2)^2 + c(2) + d$

$28 = 8a + 4b + 2c + d$

<u>Step 2: Solve using the second point</u>

<em>(-1, -5)</em>

$-5 = a(-1)^3 + b(-1)^2 + c(-1) + d$

$-5 = -a + b - c + d$

<u>Step 3: Solve using the third point</u>

<em>(4, 220)</em>

$220 = a(4)^3 + b(4)^2 + c(4) + d$

$220 = 64a + 16b + 4c + d$

<u>Step 4: Solve using the fourth point</u>

<em>(-2, -20)</em>

$-20 = a(-2)^3 + b(-2)^2 + c(-2) + d$

$-20 = -8a + 4b - 2c + d$

<u>Step 5: Combine the first and fourth equations</u>

<u /> $28 - 20 = 8a - 8a + 4b + 4b + 2c - 2c + d + d$

$8 = 8b + 2d$

$8 - 8b = 8b - 8b + 2d$

$(8 -8b)/2 = 2d/2$

$4 - 4b = d$

<u>Step 6: Solve for c in the second equation</u>

$-5 + 5 = -a + b - c + d + 5$

$0 + c = -a + b - c + c + d + 5$

$c = -a + b + d + 5$

<u>Step 7: Substitute d with the stuff we got in step 5</u>

$c = -a + b + (4 - 4b) + 5$

$c = -a + b + 4 - 4b + 5$

$c = -a - 3b + 9$

<u>Step 8: Substitute d and c into the first equation</u>

<u /> $28 = 8a + 4b + 2(-a - 3b + 9) + (4 - 4b)$

$28 = 8a + 4b - 2a - 6b + 18 + 4 - 4b$

$28 - 22 = 6a - 6b + 22 - 22$

$6 / 6 = (6a - 6b) / 6$

$1 + b = a - b + b$

$1 + b = a$

<u>Step 9: Substitute a, b, and c into the third equation</u>

$220 = 64(1 + b) + 16b + 4(-(1 + b) - 3b + 9) + (4 - 4b)$

$220 = 64 + 64b + 16b + 4(-1 - b - 3b + 9) + 4 - 4b$

$220 - 100 = 60b + 100 - 100$

$120 / 60 = 60b / 60$

$2 = b$

<u>Step 10: Find a using b = 2</u>

$a = b + 1$

$a = (2) + 1$

$a = 3$

<u>Step 11: Find c using a = 3 and b = 2</u>

$c = -a - 3b + 9$

$c = -(3) - 3(2) + 9$

$c = -3 - 6 + 9$

$c = 0$

<u>Step 12: Find d using b = 2</u>

$d = 4 - 4b$

$d = 4 - 4(2)$

$d = 4 - 8$

$d = -4$

Answer: $a = 3, b = 2, c = 0,d = -4$

6 0

2 years ago

Read 2 more answers

Use a table to compute the product below.<br><br>(3x2 + 6x + 9)(8x - 4)

jolli1 [7]

(3x²+6x+9)(8x-4)= 24x³-12x²+48x²-24x+72x-36= 24x³+36x²+48x-36
R: E

4 0

3 years ago

Lionel created a picture to hang on his wall. The drawing is below. Each circle has a radius of 8cm. The circles touch each othe

Vikki [24]

Answer:

888888

Step-by-step explanation:

88888888888888888888

7 0

1 year ago

Read 2 more answers

If f(x) =3x-5 them find values of f(3) and f(-7). please explain step by step

LenKa [72]

Answer:

f(3) = 4

f(-7) = -26

Step-by-step explanation:

Hi there!

$f(x) =3x-5$

To find f(3), replace every x with 3:

$f(3) =3(3)-5\\f(3) =9-5\\f(3) =4$

Therefore, f(3)=4.

$f(x) =3x-5$

To find f(-7), replace every x with -7:

$f(-7) =3(-7)-5\\f(-7) =-21-5\\f(-7) =-26$

Therefore, f(-7)=-26.

I hope this helps!

8 0

2 years ago

I need some help with this calculus 1 question.

Cerrena [4.2K]

Answer:

(a) f'(1)=-4

(b) y+4x-4=0

Step-by-step explanation:

<u>Tangent Line of a Function</u>

Given f(x) a real differentiable function in x=a, the slope of the tangent line of the function in x=a is given by f'(x=a). Where f' is the first derivative of f.

We are given

$y=x-x^5$

The derivative is

$y'=1-5x^4$

(a) The slope of the tangent line at (1,0) is

$f'(1)=1-5\cdot 1^4=-4$

$f'(1)=-4$

(b) The equation of the tangent line can be found with the general formula of the line:

$y-y_o=m(x-x_o)$

Where m is the slope and the point (xo,yo) belongs to the line. We have m=-4, xo=1, yo=0, thus

$y-0=-4(x-1)$

Or, equivalently

$y+4x-4=0$

3 0

2 years ago