Answer:
in steps
Step-by-step explanation:
Are you trying to prove any 3 positive consecutive odd integers whose product of the first and the third is four less than the square of the second?
3 positive consecutive odd integers: x-2, x, x+2
(x-2) (x+2)=x² - 4 ..... correct
11, 13, 15 11 x 15 = 165 = 13² - 4
Answer:
Step-by-step explanation:
Just multiply the first equation by -1 and then add them together to find x. Should look something like
-2x - y = -7
5x + y = 9
--------------------
3x + 0 = 2
x = 2/3
Now back substitute using either equation to find y. I'll use the first:
2(2/3) + y = 7
4/3 + y = 7
y = 7 - 4/3 = 21/3 - 4/3 = 17/3
Answer:
x=2/3
y=17/3
Answer:
No solution
Step-by-step explanation:
This answer has no solution, follow these steps to see how.
First, you add 7 on both sides.
Then you should have 2b > -7 +2b
You see how there is a 2b on both sides? this makes the problem unsolvable.
Say you were to continue though. You would subtract 2b on both sides and end up getting 0 > -7. Therefore there is no solution.
