Answer:
12.5% of the day
Step-by-step explanation:
There are 24 hours in 1 day
3/24 = 1/8
.125 = 12.5%
if the sphere has a diameter of 5, then its radius is half that, or 2.5.
![\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=2.5 \end{cases}\implies V=\cfrac{4\pi (2.5)^3}{3}\implies V=\cfrac{62.5\pi }{3} \\\\\\ V\approx 65.44984694978736\implies V=\stackrel{\textit{rounded up}}{65.45}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvolume%20of%20a%20sphere%7D%5C%5C%5C%5C%20V%3D%5Ccfrac%7B4%5Cpi%20r%5E3%7D%7B3%7D~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D2.5%20%5Cend%7Bcases%7D%5Cimplies%20V%3D%5Ccfrac%7B4%5Cpi%20%282.5%29%5E3%7D%7B3%7D%5Cimplies%20V%3D%5Ccfrac%7B62.5%5Cpi%20%7D%7B3%7D%20%5C%5C%5C%5C%5C%5C%20V%5Capprox%2065.44984694978736%5Cimplies%20V%3D%5Cstackrel%7B%5Ctextit%7Brounded%20up%7D%7D%7B65.45%7D)
First do 6 divided by 10
then add 8.75 to that
4a.
We can get the least number by taking LCM of 24 and 16.
We list each of the numbers as prime factors and take the mutiplication of each unique prime factor that occurs the greatest number of times.
24 = 2 * 2 * 2 * 3
16 = 2 * 2 * 2 * 2
So,
2 occurs four times
3 occurs 1 times
LCM of 24 and 16 is:
2 * 2 * 2 * 2 * 3 = 48
Least number of cheese and cracker appetizer = 48
4b.
Sleeves are sold in 24.
So, to get 48, she would need to buy:
48/24 = 2 sleeves
4c.
Cheese slices comes in packages of 16. So she needs to buy:
48/16 = 3 packages of cheese
Given:
In triangle GHJ, ∠G = 110°, ∠J = 40° and ∠H = 30°.
To find:
The answer to complete the given statements.
Solution:
According to triangle side and angle relationship, largest angle has longest opposite side and smallest angle has shortest opposite side.
∠G = 110°, ∠J = 40° and ∠H = 30°.
Here, ∠G > ∠J = 40° and ∠G > ∠H. So, ∠G is the Largest angle.
Since angle G is largest angle, the opposite side, JH, is longest.
Clearly,
110° > 40° > 30°.
∠G > ∠J > ∠H
Using triangle side and angle relationship, we get
JH > GH > GJ
The order of the side lengths from longest to shortest is JH, GH ahd GJ.
