Answer:
Here we will use algebra to find three consecutive integers whose sum is 300. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 300. Therefore, you can write the equation as follows:
(X) + (X + 1) + (X + 2) = 300
To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:
X + X + 1 + X + 2 = 300
3X + 3 = 300
3X + 3 - 3 = 300 - 3
3X = 297
3X/3 = 297/3
X = 99
Which means that the first number is 99, the second number is 99 + 1 and the third number is 99 + 2. Therefore, three consecutive integers that add up to 300 are 99, 100, and 101.
99 + 100 + 101 = 300
We know our answer is correct because 99 + 100 + 101 equals 300 as displayed above.
Step-by-step explanation:
Answer:
Step-by-step explanation:
Answer:

Step-by-step explanation:
<u>Complete Question:</u>
Angela shared a cab with her friends . When they arrived at their destination, they evenly divided the $48 fare among "j" of them . Angela gave the cab $5 tip. How much did Angela pay in total?
<u>Solution:</u>
The fare was $48 and including Angela, there were j people, so each paid:
48/j
Also, Angela paid $5 additionally.
So, Angela paid:
48/j --- when dividing evenly
5 --- as a tip
Total Angela Paid: 
Total Payment: 
Answer:
- 4 < x ≤ 7
Step-by-step explanation:
Given
- 10 ≤ - 5x + 25 < 45 ( subtract 25 from all 3 intervals )
- 35 ≤ - 5x < 20
Divide all 3 intervals by - 5, reversing the inequality signs as a consequence.
7 ≥ x > - 4
Hence - 4 < x ≤ 7