HUrRiCAn KatrINa?? MORe liKE?

The diameter of a table tennis ball is 20 millimeters.

KiRa [710]

The surface area of the table tennis ball will be around 1256.64 mm².

<h3>What is the sphere?</h3>

A sphere is a 3D geometrical object which has a radius and becomes a point that revolves around a fixed point called the center.

A sphere has surface area and volume based upon the radius of the sphere.

For example, if you have a sphere of radius r then its surface area will be 4πr² and volume will be (4/3)πr³.

The table tennis ball is the form of a sphere.

Given that,

The diameter of a table tennis ball is 20

Radius(r) = 20/2 = 10 mm

Surface area of an sphere = 4πr²

So,

Area = 4π(10)² = 1256.64 mm².

Hence "The surface area of the table tennis ball will be around 1256.64 mm²".

For more about a sphere,

brainly.com/question/9994313

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5 0

2 years ago

Read 2 more answers

5/3 ÷ (-6/7)=?<br> thank you so much :D

siniylev [52]

The answer is
Exact form: -35/18
Decimal form:-1.94444444...
Mixed number form: -1 17/18

7 0

3 years ago

The probability density function of the time to failure of an electronic component in a copier (in hours) is f(x) for Determine

salantis [7]

The question is incomplete. Here is the complete question.

The probability density function of the time to failure of an electronic component in a copier (in hours) is

$f(x)=\frac{e^{\frac{-x}{1000} }}{1000}$

for x > 0. Determine the probability that

a. A component lasts more than 3000 hours before failure.

b. A componenet fails in the interval from 1000 to 2000 hours.

c. A component fails before 1000 hours.

d. Determine the number of hours at which 10% of all components have failed.

Answer: a. P(x>3000) = 0.5

b. P(1000<x<2000) = 0.2325

c. P(x<1000) = 0.6321

d. 105.4 hours

Step-by-step explanation: <em>Probability Density Function</em> is a function defining the probability of an outcome for a discrete random variable and is mathematically defined as the derivative of the distribution function.

So, probability function is given by:

P(a<x<b) = $\int\limits^b_a {P(x)} \, dx$

Then, for the electronic component, probability will be:

P(a<x<b) = $\int\limits^b_a {\frac{e^{\frac{-x}{1000} }}{1000} } \, dx$

P(a<x<b) = $\frac{1000}{1000}.e^{\frac{-x}{1000} }$

P(a<x<b) = $e^{\frac{-b}{1000} }-e^\frac{-a}{1000}$

a. For a component to last more than 3000 hours:

P(3000<x<∞) = $e^{\frac{-3000}{1000} }-e^\frac{-a}{1000}$

Exponential equation to the infinity tends to zero, so:

P(3000<x<∞) = $e^{-3}$

P(3000<x<∞) = 0.05

There is a probability of 5% of a component to last more than 3000 hours.

b. Probability between 1000 and 2000 hours:

P(1000<x<2000) = $e^{\frac{-2000}{1000} }-e^\frac{-1000}{1000}$

P(1000<x<2000) = $e^{-2}-e^{-1}$

P(1000<x<2000) = 0.2325

There is a probability of 23.25% of failure in that interval.

c. Probability of failing between 0 and 1000 hours:

P(0<x<1000) = $e^{\frac{-1000}{1000} }-e^\frac{-0}{1000}$

P(0<x<1000) = $e^{-1}-1$

P(0<x<1000) = 0.6321

There is a probability of 63.21% of failing before 1000 hours.

d. P(x) = $e^{\frac{-b}{1000} }-e^\frac{-a}{1000}$

0.1 = $1-e^\frac{-x}{1000}$

$-e^{\frac{-x}{1000} }=-0.9$

${\frac{-x}{1000} }=ln0.9$

-x = -1000.ln(0.9)

x = 105.4

10% of the components will have failed at 105.4 hours.

5 0

4 years ago

Use the unit circle to find the value of sec (0)

Mekhanik [1.2K]

According to unit circle the value of (0) is o

3 0

3 years ago

Bill needs to edge his yard with the dimensions in the shape below. What distance will he have walked after completing his edgin

Montano1993 [528]

Answer:

37.8 m

Step-by-step explanation:

The computation of the distance is shown below:

In triangle ADE

$AD^2 = AE^2 + DE^2 \\\\ AD^2 = 5^2 + 3^2 \\\\ AD^2 = 34$

AD = 5.8

Now the distance walked after completing his edging is

Distance = AD + AB + BC + CD

= 5.8 + 12 + 5 + 15

= 37.8 m

We simply added these four sides so that the correct distance could arrive

Hence, the distance walked after completing his edging is 37.7

5 0

3 years ago