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Stells [14]
3 years ago
7

What % of 40 is 15? Please put how u do it

Mathematics
2 answers:
andriy [413]3 years ago
6 0

Answer:

37.5

Step-by-step explanation:

so x% of 40 is 15

the equation for that is

x/100 * 40 = 15

40x/100 = 15

multiply 100 on both sides

40x = 1500

divide 40 on both sides

37.5

37.5% of 40 is 15

telo118 [61]3 years ago
6 0

Answer:

37.5

Step-by-step explanation:

Just do 15 out of 40 and divide 15 by 40 for the answer.

40/15

add a zero to the 15

40 goes into 150 3 times (40*3= 120)

150-120=30

40 doesn't go into 30 so you add another 0 which makes it 300

40 goes into 300 7 times

300-280= 20

40 doesn't go into 20 so add another zero (200)

40 goes into 200 5 times (40*5=200)

37.5

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Answer:

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Step-by-step explanation:

y+3/2=x+3

y+3/2-3=x

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Mackenzie has d dimes and a quarters. She has a minimum of $3 worth of coins altogether. Write this situation as an inequality.
Vedmedyk [2.9K]

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Step-by-step explanation:

d = dimes and a = quarters

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(2^8 ⋅ 3^−5 ⋅ 6^0)^−2 ⋅ 3 to the power of negative 2 over 2 to the power of 3, whole to the power of 4 ⋅ 2^28 (5 points)
Otrada [13]

Answer:

Step-by-step explanation:

(2^8 ⋅ 3^−5 ⋅ 6^0)^−2 ⋅ 3

(2^8 ⋅ 3^−5 ⋅ 6^0)^−6

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So,

(2^8*-6) * (3^−5*-6) * (6^0*-6)

(2^-48) (3^30) (6^0)

a^0=1

So,

(2^-48) (3^30) (1)

<u>(2^-48) (3^30)</u>

I hope this helps you friend!

3 0
3 years ago
9
Brums [2.3K]

Answer:

9x?lax+1)-1(2x+i)=0 p²-8p+4=0. (2x+1)(9x2-1)=0. 0-81764-40X4). (2x+1)(3x +1 (3x-1)=0 x= -1/2 x=-1/2 x=1/3. P= 843-4+213 x={-1/23 - 1 3 3 3 3 3. 4. Let 'n(x)=x2-Ox and g(x)=2x-7. Find all values of x, for which h(x) = g(x).

Step-by-step explanation:

Sheet #14-1. Quadratic Equations: Solving in Factored form. Algebra Common Core. MOVING WORDS. ... X+4 = 0 1 x +9=0 nr 3-01n-10-0 h=0 h-14=0. -4 -4 -9 -9. -3-3 tiu to. +14 114. X = -4 x=-9 n=-31 n =10 h = 14.

8 0
3 years ago
Simplify the expression 6C2
iVinArrow [24]

Answer:

^6C_2=15

Step-by-step explanation:

Recall the formula:

^nC_r=\frac{n!}{(n-r)!r!}

We apply this formula to simplify ^6C_2

This implies that:

^6C_2=\frac{6!}{(6-2)!2!}

^6C_2=\frac{6!}{4!2!}

^6C_2=\frac{6\times5\times4!}{4!\times 2\times1}

This simplifies to

^6C_2=\frac{6\times5}{2\times1}

^6C_2=\frac{3\times5}{1\times1}=15

8 0
3 years ago
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