Area of triangle = base x height /2
48 = (a+14)a/2
a^2 +14a = 96
a^2 + 14a - 96 = 0
Solving for a = 5.04
The equation of the line is y = -11x + 232
<h3>How to determine the equation?</h3>
The given parameters are:
Slope (m)= -11
Point (x1, y1) = (31, -109)
The linear equation is then calculated as:
y = m(x - x1) + y1
This gives
y = -11(x - 31) - 109
Evaluate the product
y = -11x + 341 - 109
Evaluate the like terms
y = -11x + 232
Hence, the equation of the line is y = -11x + 232
Read more about linear equations at:
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Here. Remember to get the correct units. If you need extra help, I am more than willing to help!
Part A:
Function A:
Slope = (7-3)/(5-3) = 4/2 = 2
Equation:
y - 3 = 2(x - 3)
y - 3 = 2x - 6
y = 2x - 3
Funcion B:
(0, 3 ) and (-5, 0)
Slope = (3 - 0)/(0 + 5) = 3/5
y-intercept (0,3) so b = 3
Equation:
y = 3/5 x + 3
Function C:
y = 3x + 1
Part B:
Rate of change is the change in y over the change in x (rise/run). It's also the slope
Function A: rate of change = 2
Function B: rate of change = 3/5 (smallest)
Function C: rate of change = 3 (largest)
Order linear functions based on rate of change from least to greatest.
Function B: y = 3/5 x + 3
Function A: y = 2x - 3
Function C: y = 3x + 1