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blondinia [14]
3 years ago
9

2x + 2 = x + 3 Please help asap

Mathematics
1 answer:
siniylev [52]3 years ago
7 0
X =1 because you subtract the 2 from the 3 and the 2x -x
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Use formulas to find the lateral area and surface area of the given prism. Round your answer to the nearest whole number. The fi
mel-nik [20]

Answer:

Lateral Surface Area = 472 m²

Total Surface Area = 486m²

Step-by-step explanation:

The above prism is a Triangular prism

a) Lateral Surface Area = Perimeter of the Base × H

H = 29m

Perimeter of the Base = (7m + 7.28m + 2m)

= 16.28m

Lateral Surface Area = 16.28m × 29m

= 472.12 m²

Approximately to the nearest whole number = 472 m²

b) Total Surface Area

Triangular prism =

2 Triangles and 3 Rectangles

1st Triangle = 1/2 × base × Height

= 1/2 × 2m × 7m

= 7m²

2nd Triangle = 1/2 × base × height

= 1/2 × 2m × 7m

= 7m²

1st Rectangle = Length × Width

= 29m × 2m = 58m²

2nd Rectangle =

Length × Width

= 29m × 7.28m = 211.12m²

Length × Width

= 29m × 7m = 203m²

Total surface area = 7m² + 7m² + 58m² + 211.12m² + 203m²

= 486.12m²

Approximately to the nearest whole number = 486 m²

Option A is the correct option

6 0
3 years ago
In ΔBCD, the measure of ∠D=90°, the measure of ∠C=83°, and DB= 1.3feet. What is the length of CD to the nearest tenth of a foot.
Lina20 [59]

Answer:

CD\approx0.2

Step-by-step explanation:

By the tangent ratio, tanC=\frac{DB}{CD}. Substituting the given values into this equation gives us:

tan83° = \frac{1.3}{CD}

CD*tan83° =1.3 (Multiply both sides of the equation by CD)

CD=\frac{1.3}{tan83\textdegree} (Divide both sides of the equation by tan83\textdegree)

CD=0.15962\approx0.2

Hope this helps!

3 0
2 years ago
Aba's dog was 5 1/2 inches tall when it was a puppy but is now 14 inches tall. Aba's dog grew n-inches.
tino4ka555 [31]

Answer:

8.5 inches

Step-by-step explanation:

To find the height of Aba's dog -

Subtract 5 1/2 from 14 to find the amount she grew:

The result should be 8.5 or 8 1/2.

So Aba's dog grew 8.5 inches.

4 0
2 years ago
Triangle ABC is transformed to obtain triangle A′B′C′:
Lisa [10]

Answer:

Option C is right.

Step-by-step explanation:

Given is a graph with two triangles marked on it.

Triangle ABC is in the I quadrant with vertices (2,2) (2,10) and (8,12)

Triange A'B'C' is in the III quadrant with vertices (-1,-1), (-1,-5) and (-4,-6)

On comparison we find corresponding side of AB is A'B'

Length of AB = 8 and Length of A'B' = 4.

Hence A'B'C' is obtained by dilating ABC by a scale factor of 1/2.

Now since moved to III quadrant from I quadrant we find that there is a rotation of triangle ABC about the origin.  The degree of rotation is 180 degrees.

Hence A'B'C' is obtained by dilating ABC by a scale factor of 1/2 and then rotating it about the origin by 180 degrees

8 0
3 years ago
the perimeter of a rectangle is 55 inches. the ratio of the length to width is 7:4. use proportions to find the area of the rect
Leni [432]

Answer:

Step-by-step explanation:

let : x the length and y the width    .... ( x  > y and x ; y reals numbers )

the perimeter is : 2(x+y)

2(x+y) = 55...(1)

x/y = 7/4 ...(2)

by (2) : x = (7/4)y

subsct in (1) : 2( (7/4)y +y ) =55

(7/2)y +2y =55

multiply by 2

7y +4y = 110

11y = 110

y = 10

x = (7/4)(10)

x = 35/2

4 0
3 years ago
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