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2 years ago

May someone help me please

Mathematics

1 answer:

AlekseyPX2 years ago

3 0

Discount amount: $160.20
Sale price: $729.80

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You need a 50% solution. On hand, you have a 200 mL of a 35% alcohol mixture. You also have 70% alcohol mixture. How much of the

CaHeK987 [17]

Answer:

150 mL

Step-by-step explanation:

We need a mixture that is at 50%, now we have 200 mL at 35% and another mixture that is at 70%, that is, we must calculate how much of this mixture is added, by the following equation

200 * 35% + x * 70% = 50% (x + 200)

70 + 0.7 * x = 0.5 * x + 100

0.7 * x - 0.5 * x = 100 - 70

0.2 * x = 30

x = 30 / 0.2

x = 150

150 mL must be added so that the mixture is 50%.

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2 years ago

What is the y-intercept of the line?<br><br> y= -2x - 8<br><br> y-intercept =

ivolga24 [154]

Like I said on the other question. Slope will ALWAYS be the number beside x and y-intercept will always be after that.

Slope-intercept form = y = mx + b

Slope goes where m is and y-intercept goes where b is.

Hope this helps!

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3 years ago

Read 2 more answers

Solve using substitution y=x-3 4x+y=32

hichkok12 [17]

Hey there !

Check the attachment.
Hope it helps you :)

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2 years ago

At the city Museum child admission is $5.40 and adult admission is $8.50 on Thursday 151 tickets were sold for a total sales of

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About 202 child tickets were sold that day.

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2 years ago

A company logo is made up of a square and three identical triangles.

IgorLugansk [536]

Answer:

$the \: area \: of \: the \: logo \: is \: {91cm}^{2}$

Step-by-step explanation:

To determine the area of the logo you have to calculate the area of the triangle and the square that comform it and then add the four areas.

Area of the square.

To calculate the area of the square you have to calculate the square of one of its sides, following the formula:

$a = {a}^{2}$

Where "a" is the length of one of its side.

The side length of the square is a=7cm, so its area will be:

$asquare = {7}^{2} \\ asquare = {49cm}^{2}$

Area of the triangles.

The three triangles are equal, they have a base equal to the side of the square, i.e. with a length of 7cm, and their height is h=4cm.

To calculate the area of one triangle, you have to multiply its base by its height and divide by 2, following the formula:

$a = \frac{b.h}{2} \\ a = \frac{7.4}{2} \\ a = \frac{28}{2} \\ a = {14cm}^{2}$

The area calculated the correspond to one triangle, since all triangles are congruent, you have to multiply the said area by 3 to determine the area of three figures:

$atriangles = 3a \\ atriangles = {42cm}^{2}$

Now that the area of all shape are calculated, you have to add them to determine the area of the logo:

$alogo = asquare + atriangle \\ alogo = 49 + 42 \\ alogo = {91cm}^{2}$

4 0

3 years ago