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Stella [2.4K]
3 years ago
15

Use the circle to answer the questions.

Mathematics
2 answers:
aliina [53]3 years ago
5 0

~H~e~l~l~o~! ☺

ᴘʀᴏᴏꜰ ɪꜱ ꜱʜᴏᴡɴ ʙᴇꜰᴏʀᴇ ᴏꜰ ᴛʜᴇ Qᴜᴇꜱᴛɪᴏɴ :

ᴄᴀᴜꜱᴇ, ɪ ᴅɪᴅ ᴛʜɪꜱ ʙᴇꜰᴏʀᴇ!

Hope It Helped!

<u>And Tell me if The answer is wrong. . .</u>

<u />

<h2><u>Good Luck With Your Assignment!</u></h2><h2><u /></h2>

#LearnWithBrainly

~A~n~s~w~e~r~ :

ᴊᴀᴄᴇ ノシ

kipiarov [429]3 years ago
5 0

Answer:

yes, the person above me is correct as well

Step-by-step explanation:

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Find the area.
frozen [14]

Answer:

Area of triangle = 1/2×base×height

= 1/2×37×30

= 555m²

3 0
3 years ago
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A father is eight times as old as his son . In 10 years , he will be three times as old as his son . The age of son is
vodka [1.7K]

Answer:

The son is 4years old

Step-by-step explanation:

Let the son's age=x

the father's age=8x

IN 10YEARS,

Son's age=x+10

father's age=8x+10

Equate them

8x+10=3(x+10)

8x+10=3x+30

5x=20

x=4

6 0
3 years ago
Which is greater 0.6 or 0.06
antiseptic1488 [7]
0.6
hope this helps!!!
6 0
3 years ago
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What is all that is equivalent to 5x+(x+6)+3x
Trava [24]

Answer:

9x+6

Step-by-step explanation:

I think by equivalent, you mean solve it.

5x+(x+6)+3x

5x+x+6+3x, open the parenthesis

9x+6, add up the like terms

6 0
3 years ago
Suppose u and v are functions of x that are differentiable at x=0 and that u(0)=4, u′(0)=7, v(0)=2 and v′(0)=1. Find the values
Leona [35]

Answer with Step-by-step explanation:

We are given that u and v are functions of x and both are differentiable at x=0

u(0)=4,u'(0)=7,v(0)=2,v'(0)=1

a.We have to find the values of \frac{d(uv)}{dx}

\frac{d(u\cdot v)}{dx}=u'v+uv'

Using this formula

Then , we get

[\frac{d(uv)}{dx}]_{x=0}=u'(0)v(0)+u(0)v'(0)=7(2)+4(1)=14+4=18

[\frac{d(uv)}{dx}]_{x=0}=18

b.\frac{d(u/v)}{dx}=\frac{u'v-uv'}{v^2}

[\frac{d(u/v)}{dx}]_{x=0}=\frac{u'(0)v(0)-u(0)v'(0)}{v^2(0)}=\frac{7(2)-4(1)}{2^2}=\frac{14-4}{4}=\frac{10}{4}=\frac{5}{2}

[\frac{d(u/v)}{dx}]_{x=0}=\frac{5}{2}

c.

[\frac{d(v/u)}{dx}]_{x=0}=\frac{v'(0)u(0)-v(0)u'(0)}{u^2(0)}=\frac{1(4)-7(2)}{4^2}

[\frac{d(v/u)}{dx}]_{x=0}=\frac{-10}{16}=\frac{-5}{8}

d.\frac{d(-6v-9u)}{dx}=-6v'-9u'

[\frac{d(-6v-9u)}{dx}]_{x=0}=-6v'(0)-9u'(0)=-6(1)-9(7)=-6-63=-69

[\frac{d(-6v-9u)}{dx}]_{x=0}=-69

3 0
3 years ago
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