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svlad2 [7]
3 years ago
8

Help please :( and thanks!!!

Mathematics
2 answers:
victus00 [196]3 years ago
6 0
C is the answer I’m 99% sure :)
Oxana [17]3 years ago
4 0
C is the correct answer
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What is the y-intercept of the graph of the equation y=4x(3x) A; (0,4) B: (0,3) C;(0,12) D:(0,8)
Alchen [17]

Answer:

To find y intercept x should be 0.

And in this.

Y=4x.3x

Y=4*0*3*0

Y=0 answer.

4 0
2 years ago
Calculate the gradient of the straight line which joins A(2,-3) and B(6,9)<br>​
Pie

Answer:

Gradient: m = 3

Step-by-step explanation:

m = change in y/change in x

m = \frac{Y2-Y1}{X2-X1}

m = \frac{9-(-3)}{6-(2)}

m = 12/4

m = 3

5 0
3 years ago
Find a compact form for generating functions of the sequence 1, 8,27,... , k^3
pantera1 [17]

This sequence has generating function

F(x)=\displaystyle\sum_{k\ge0}k^3x^k

(if we include k=0 for a moment)

Recall that for |x|, we have

\displaystyle\frac1{1-x}=\sum_{k\ge0}x^k

Take the derivative to get

\displaystyle\frac1{(1-x)^2}=\sum_{k\ge0}kx^{k-1}=\frac1x\sum_{k\ge0}kx^k

\implies\dfrac x{(1-x)^2}=\displaystyle\sum_{k\ge0}kx^k

Take the derivative again:

\displaystyle\frac{(1-x)^2+2x(1-x)}{(1-x)^4}=\sum_{k\ge0}k^2x^{k-1}=\frac1x\sum_{k\ge0}k^2x^k

\implies\displaystyle\frac{x+x^2}{(1-x)^3}=\sum_{k\ge0}k^2x^k

Take the derivative one more time:

\displaystyle\frac{(1+2x)(1-x)^3+3(x+x^2)(1-x)^2}{(1-x)^6}=\sum_{k\ge0}k^3x^{k-1}=\frac1x\sum_{k\ge0}k^3x^k

\implies\displaystyle\frac{x+4x^3+x^3}{(1-x)^4}=\sum_{k\ge0}k^3x^k

so we have

\boxed{F(x)=\dfrac{x+4x^3+x^3}{(1-x)^4}}

5 0
3 years ago
How do you say 33 091 in word
LekaFEV [45]
Thirty three thousand and ninety one
5 0
3 years ago
Read 2 more answers
Michael needs at least $200 to buy airpods. He already has $50. If he saves $15 each week, how many weeks will it take for Micha
DerKrebs [107]

Answer:

it will take him 3 weeks to reach is goal.

Step-by-step explanation:

if michael needs $200 and he already has 50 then 200-50 is 150. then you divide 150 divided by 15 to get 3

hopethis helped.

3 0
2 years ago
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