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Anit [1.1K]
3 years ago
12

The first picture shows the numbers you will use to put on the number line where the number falls in. The 2 picture shows the nu

mber line where you will need to put the numbers on the number line between each category that the numbers have on the number line. where do the numbers in the first picture go on the number line ??

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
3 0
I’m sorry that this isn’t an answer but if you need help I use socratic!
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Step-by-step explanation:

<em>Hello</em><em>,</em>

<em>I</em><em> </em><em>hope</em><em> </em><em>you</em><em> </em><em>mean</em><em> </em><em>to</em><em> </em><em>cancel</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factor</em><em> </em><em>that</em><em> </em><em>exists</em><em> </em><em>in</em><em> </em><em>numerator</em><em> </em><em>and</em><em> </em><em>denominator</em><em>,</em><em>right</em><em>.</em>

<em>so</em><em>,</em><em> </em><em>Let's</em><em> </em><em>look</em><em> </em><em>for</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factor</em><em>, </em>

<em>here</em><em>,</em><em> </em><em>the</em><em> </em><em>expression</em><em> </em><em>is</em><em>, </em>

<em>=</em><em>4</em><em>(</em><em>x-2</em><em>)</em><em>/</em><em> </em><em>(</em><em>x</em><em>+</em><em>5</em><em>)</em><em>(</em><em>x-2</em><em>)</em>

<em>so</em><em>,</em><em> </em><em>here</em><em> </em><em>we</em><em> </em><em>find</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factor</em><em> </em><em>is</em><em> </em><em>(</em><em>x-2</em><em>)</em>

<em>now</em><em>,</em><em> </em><em>we</em><em> </em><em>have</em><em> </em><em>to</em><em> </em><em>cancel</em><em> </em><em>it</em><em>.</em><em> </em><em>And</em><em> </em><em>after</em><em> </em><em>cancelling</em><em> </em><em>we</em><em> </em><em>get</em><em>,</em>

<em>=</em><em>4</em><em>/</em><em>(</em><em>x</em><em>+</em><em>5</em><em>)</em>

<em>Note</em><em>:</em><em>{</em><em> </em><em>we</em><em> </em><em>cancel</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factor</em><em> </em><em>if</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factors</em><em> </em><em>are</em><em> </em><em>in</em><em> </em><em>multiply</em><em> </em><em>form</em><em>.</em><em>}</em>

<em><u>Hope it helps</u></em><em><u> </u></em>

3 0
3 years ago
1) In class you worked with a "big" cube made of 27 smaller cubes each of which was 1 cmby 1 cm by 1 cm. Suppose you had 150 of
abruzzese [7]

The information provided is that you have smaller cubes that measure 1 cm on either of the three sides. In order words if you lie each cube side by side you would have the length/width/height of the indicate sides.

For a cube made up of 27 smaller cubes, you can determine the length of each side by factoring the entire size provided. That means for a cube made up of 27 smaller cubes you would have;

27=3\times3\times3

This means you would have 3 smaller cubes on the length, 3 smaller cubes on the width and 3 smaller cubes on the height.

Therefore, if you now have 150 of the smaller cubes, by factoring this you would have the following possibility;

\begin{gathered} 150=2\times3\times5\times5 \\ 150=6\times5\times5 \end{gathered}

This means you would have one side (length) 6 cubes, on another side (width) 5 cubes and on the third side (height) 5 cubes.

That means with 150 smaller cubes you could make a cube with the dimensions,

\begin{gathered} \text{Length}=6\operatorname{cm} \\ \text{Width}=5\operatorname{cm} \\ \text{Height}=5\operatorname{cm} \end{gathered}

ANSWER:

The largest big cube you could make would be a 6 cm by 5 cm by 5cm big cube

6 0
2 years ago
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