Answer:
Scale factor = 3
Step-by-step explanation:
Using similar triangles
AT/AG = AB/AC
9/3 = x+10/3x-10
Cross multiply
3(x+10) = 9(3x-10)
Expand
3x+30 = 27x-90
3x-27x = -90 - 30
-24x = -120
x = 120/24
x = 5
For the larger triangle;
AC = 3x-10
AC = 3(5)-10
AC =15-10
AC = 5
AB = x+10
AB = 5+10
AB = 15
For the scale factor;
Since AT/AG = AB/AC
9/15 = 3/5
3*3/5*3 =3/5
Since the numerator and denominator of the larger triangle is multiplies by the same factor i.3 3. Hence the scale factor is 3
All estimating problems make the assumption you are familar with your math facts, addition and multiplication. Since students normally memorize multiplication facts for single-digit numbers, any problem that can be simplified to single-digit numbers is easily worked.
2. You are asked to estimate 47.99 times 0.6. The problem statement suggests you do this by multiplying 50 times 0.6. That product is the same as 5 × 6, which is a math fact you have memorized. You know this because
.. 50 × 0.6 = (5 × 10) × (6 × 1/10)
.. = (5 × 6) × (10 ×1/10) . . . . . . . . . . . by the associative property of multiplication
.. = 30 × 1
.. = 30
3. You have not provided any clue as to the procedure reviewed in the lesson. Using a calculator,
.. 47.99 × 0.6 = 28.79 . . . . . . rounded to cents
4. You have to decide if knowing the price is near $30 is sufficient information, or whether you need to know it is precisely $28.79. In my opinion, knowing it is near $30 is good enough, unless I'm having to count pennies for any of several possible reasons.
Answer:
84? Not sure but pretty sure
Step-by-step explanation:
In a straight line, the word can only be spelled on the diagonals, and there are only two diagonals in each direction that have 2 O's.
If 90° and reflex turns are allowed, then the number substantially increases.
Corner R: can only go to the adjacent diagonal O, and from there to one other O, then to any of the 3 M's, for a total of 3 paths.
2nd R from the left: can go to either of two O's, one of which is the same corner O as above. So it has the same 3 paths. The center O can go to any of 4 Os that are adjacent to an M, for a total of 10 more paths. That's 13 paths from the 2nd R.
Middle R can go the three O's on the adjacent row, so can access the three paths available from each corner O along with the 10 paths available from the center O, for a total of 16 paths.
Then paths accessible from the top row of R's are 3 +10 +16 +10 +3 = 42 paths. There are two such rows of R's so a total of 84 paths.
Answer:
2.9
Step-by-step explanation:
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