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Dennis_Churaev [7]
3 years ago
12

Carl is raising money for his football team. He is selling chocolate bars for $1.50 each and cookies for $2. He sold all 20 of h

id chocolate bars. Carl wants to raise at least $55 for his team. Which inequality represents the minimum number.Of cookies. C, carl has to sell in irder to meet his goal
Mathematics
1 answer:
stich3 [128]3 years ago
7 0

Answer:

Carl has to sell at least 8 cookies.

c\geq 7.5

Step-by-step explanation:

Carl gets \$1.50 by selling 1 chocolate bar.

Earning from chocolate bars:

Total\ chocolate\ bar=20\\\\Earning\ from\ one\ chocolate\ bar=\$1.50\\\\Total\ earning\ from\ chocolate\ bar=Total\ chocolate\ bar\times cost\ of\ 1\ chocolate\ bar=20\times 1.5=\$30

Earning From cookies:

Let\ total\ number\ of\ cookies=c\\\\Cost\ of\ 1\ cookie=\$2\\\\Earning\ from\ cookies=2\times c=2c

Total\ earning=Earning\ from\ cookies+Earning\ from\ cookies+Earning\ from\ chocolate\ bars\\\\Total\ earning=30+2c

Carl wants to raise at least \$55

Total\ earning\geq 55\\\\2c+30\geq 55\\\\2c\geq 55-30\\\\2c\geq 15\\\\c\geq7.5

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Answer:

a = 3, b = 0, c = 0, d = -2

Step-by-step explanation:

<em>To find the reflection Multiply the matrices</em>

∵ The dimension of the first matrix is 2 × 2

∵ The dimension of the second matrix is 2 × 3

<em>1. Multiply the first row of the 1st matrix by each column in the second matrix add the products of each column to get the first row in the 3rd matrix.</em>

2. Multiply the second row of the 1st matrix by each column in the second matrix add the products of each column to get the second row of the 3rd matrix

\left[\begin{array}{ccc}1&0\\0&-1\end{array}\right]  × \left[\begin{array}{ccc}0&3&0\\0&0&2\end{array}\right]  = \left[\begin{array}{ccc}(1*0+0*0)&(1*3+0*0)&(1*0+0*2)\\(0*0+-1*0)&(0*3+-1*0)&(0*0+-1*2)\end{array}\right]=\left[\begin{array}{ccc}0&3&0\\0&0&-2\end{array}\right]

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7 0
3 years ago
After studying the diagram shown, Michael makes the following conclusions:
inn [45]

Answer:

Therefore, Michael concludes option C)

C)(DA)^{2}=(DG)^{2}+(AG)^{2}

Step-by-step explanation:

Given:

1. DG = 3 and the area of square DEFG is 9.

2. AG = 4 and the area of square GHIA is 16.

3. DA = 5 and the area of square ABCD is 25.

So we have,

(DG)^{2}=3^{2}=9\\ \\(AG)^{2}=4^{2}=16\\\\(DA)^{2}=5^{2}=25\\

Now Add DG² and AG² we get

(DG)^{2}+(AG)^{2}=9+16=25=(DA)^{2}

Which is also called as  Pythagoras theorem i.e

(\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}

Therefore, Michael concludes option C)

C)(DA)^{2}=(DG)^{2}+(AG)^{2}

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3 years ago
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abruzzese [7]
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3 years ago
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dsp73

Answer:

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Step-by-step explanation:

Variables and symbols:

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Volume of a sphere in terms of radius:

V = \frac{4}{3}\pi r^3 , V \approx 4.1888r^3

To calculate the volume of a sphere:

Usually the hardest part is measuring or estimating the diameter of the sphere. Special tools exist for smaller parts like balls in ball-bearings, but it gets more complicated if the size is large. Knowing that the diameter is the largest internal measurement you can take should help.

Once you have the measurement, to find the volume use the formula above, in which π is the well-known mathematical constant equal to about 3.14159. To adjust for a half-sphere calculation, just divide the result by two.

Spheres and half-spheres are useful in engineering and architecture due to their property of being able to take equal amounts of pressure or force from each direction.

Solution:

V=\frac{4}{3} \pi r^{3} =\frac{4}{3} *\pi *7^{3}  \approx1436.75504

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