All categories

3 years ago

A and b are complementary angles and a and c are supplementary angles. If a=xº, (a) express b and c in terms of x

Mathematics

1 answer:

kirza4 [7]3 years ago

3 0

Step-by-step explanation:

a + b = 90

a + c = 180

a) If a = x, the. we can write

x + b = 90 and x + c = 180

b = 90 - x

c = 180 - x

b) c - b = (180 - x) - (90 - x)

= 180 - x - 90 + x

= 90

You might be interested in

An online furniture store sells chairs for $150 each and tables for $550 each. Every day, the store can ship a maximum of 40 pie

Katen [24]

Answer:

minimum of 13 chairs must be sold to reach a target of $6500

and a max of 20 chairs can be solved.

Step-by-step explanation:

Given that:

Price of chair = $150

Price of table = $400

Let the number of chairs be denoted by c and tables by t,

According to given condition:

t + c = 30 ----------- eq1

t(150) + c(400) = 6500 ------ eq2

Given that:

10 tables were sold so:

t = 10

Putting in eq1

c = 20 (max)

As the minimum target is $6500 so from eq2

10(150) + 400c = 6500

400c = 6500 - 1500

400c = 5000

c = 5000/400

c = 12.5

by rounding off

c = 13

So a minimum of 13 chairs must be sold to reach a target of $6500

i hope it will help you! mark me as brainliest pls

§ALEX§

6 0

3 years ago

Convert to the product of multiplication<br>a^2-b^2-4b-4

kirill [66]

$a^2-b^2-4b-4$ in form of multiplication is $(a-b)(a+b)-4(b+1)$ .

<u>Step-by-step explanation:</u>

We know that factors are the numbers that are being multiplied together . As 6532*7 = 45724 .Here 6532 & 7 are the factors and 45724 is product of the factors .

Here , we need to convert to the product of multiplication

a^2-b^2-4b-4 or , $a^2-b^2-4b-4$ :

⇒ $a^2-b^2-4b-4$

We know by identity that , $p^2-q^2 = (p-q)(p+q)$

⇒ $(a-b)(a+b)-4b-4$

Taking common term out as -4 :

⇒ $(a-b)(a+b)-4(b+1)$

Therefore , $a^2-b^2-4b-4$ in form of multiplication is $(a-b)(a+b)-4(b+1)$ .

7 0

3 years ago

Learning Theory Students in a psychology experiment were given an exam and then retested monthly with equivalent exams. The aver

forsale [732]

Answer:

Step-by-step explanation:

The average scores s (on a 100 point scale) for the students can be modeled by

s = 75 - 6 In(t + 1), 0 < t < 12

where t is the time in months.

a) Since the students were given an exam and then retested monthly with equivalent exams, then,

For the original exam, t = 0

Therefore,

s = 75 - 6 In(0 + 1) = 75 - 6 In1

s = 75 - 6 × 0 = 75

b) the average score after 4 months, t = 4

Therefore,

s = 75 - 6 In(4 + 1) = 75 - 6 In5

s = 75 - 9.66 = 65.34

c) s = 60

Therefore,

60 = 75 - 6 In(t + 1)

6 In(t + 1) = 75 - 60 = 15

In(t + 1) = 15/6 = 2.5

t + 1 = e^2.5 = 12.18

t = 12.18 - 1 = 11.18

t = 11 approximately

8 0

3 years ago

Find u, v , u , v , and d(u, v) for the given inner product defined on Rn. u = (0, −4), v = (5, 3), u, v = 3u1v1 + u2v2

tigry1 [53]

Answer:

$=-12$

$d(u,v)=2\sqrt{31}$

Step-by-step explanation:

We are given that inner product defined on $R_n$

$=3u_1v_1+u_2v_2$

u=(0,-4),v=(5,3)

We have to find the value of <u,v> and d(u,v)

We have $u_1=0,u_2=-4,v_1=5,v_2=3$

Substitute the value then we get

$=3(0\cdot5)+(-4)(3)=-12$

Now, $d(u,v)=\left \|v-u\right \|$

Using this formula we get

$d(u,v)=\left \| (5,7) \right \|=\sqrt{3(5)^2+(7)^2}=\sqrt{75+49}=\sqrt{124}$

$d(u,v)=2\sqrt{31}$

7 0

3 years ago

What is the measure of a third angle of this triangle

8_murik_8 [283]

All triangles add up to 180 so it’s 20°

7 0

2 years ago