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Ira Lisetskai [31]
2 years ago
10

A student concludes that for all values of x,x^2+x+1 produces a prime number. Which value of x serves as counterexample to prove

this conclusion false?

Mathematics
1 answer:
Dafna11 [192]2 years ago
5 0

Answer:

j

Step-by-step explanation:

Substitute the given values into x² + x + 1 and check if result is prime

x = - 4

(- 4)² - 4 + 1 = 16 - 4 + 1 = 13 ← prime

(- 2)² - 2 + 1 = 4 - 2 + 1 = 3 ← prime

(- 3)² - 3 + 1 = 9 - 3 + 1 = 7 ← prime

4² + 4 + 1 = 16 + 4 + 1 = 21 ← not prime

x = 4 serves as a counterexample to disprove this conclusion

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<u>Given</u>

  • a = m(2) + 2
  • value of a when m = -3

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The equation which gives the correct value of n, the number of GB, for which Plans A and B cost the same is 8n = 20 + 6(n-2)

To determine which equation gives the correct value of n, the number of GB, for which Plans A and B cost the same, we will first solve the equations.

  • For the first equation

8n = 20 + 6n

Collect like terms

8n - 6n = 20

2n = 20

Then, n = 20 ÷ 2

n = 10 GB

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For Plan B

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8n = 20(2n) + 6

First, clear the bracket

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Now, collect like terms

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For Plan A

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Here, 1/7GB will cost 1/7 × $8 = $1.14

For Plan B

$20 for the first 2GB and $6 for each additional GB after the first 2

Here, 1/7GB will cost $20 (Since the lowest cost is $20)

∴ Plans A and B do not cost the same here.

  • For the third equation

8n = 20 + 6(n-2)

First, clear the brackets

8n = 20 + 6n - 12

Now, collect like terms

8n - 6n = 20 - 12

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Here, 4GB will cost $20 + (2 × $6) = $20 + $12 = $32

Plans A and B do not cost the same here.

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Collect like terms

8n - 2n = 20 + 6

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n = \frac{26}{6}

n = \frac{13}{3} GB or 4\frac{1}{3} GB

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Here, 4\frac{1}{3}GB will cost $20 + ( 2\frac{1}{3}× $6) = $20 + $14 = $34

∴ Plans A and B do not cost the same here.

Hence, the equation which gives the correct value of n, the number of GB, for which Plans A and B cost the same is 8n = 20 + 6(n-2)

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