Question

Find the value of c that completes the square

Answer 1

Answer:

The value of c is 1/2

Step-by-step explanation:

We have to find the value of c that completes the square  $x^2-x+c$

So, completing square is of form: $a^2-2ab+b^2=(a-b)^2$

In the question given the value c can be found by breaking the middle term. we are given -x while the general formula is 2ab for middle term so, our c = 1/2 i.e 2(x)(1/2) we get x so, solving:

$x^2-x+c\\=x^2-2(x)(\frac{1}{2})+(\frac{1}{2})^2-(\frac{1}{2})^2\\=(x-\frac{1}{2})^2-(\frac{1}{2})^2$

The value of c is 1/2