Answer: type the label in A1 and use autofill
Explanation:
Took the final 2021 Edgeunity
Answer:
The following code is written in java programming language:
//set if statement
if (((modelYear >= 1999) && (modelYear <= 2002) && (modelName == "Extravagant")) || ((modelYear >= 2004) && (modelYear <= 2007) && (modelName == "Guzzler")))
{
recalled = true; //initialized Boolean value
}
else //set else statement
{
recalled = false; ////initialized Boolean value
}
Explanation:
Here, we set the if statement and set condition, if the value of modelYear is greater than equal to 1999 and less that equal to 2002 and modelName is equal to "Extravagant" or the value of modelYear is greater than equal to 2004 and less than equal to 2007 and the model year is equal to "Guzzler", than "recalled" initialized to "true".
Otherwise "recalled" initialized to "true".
It should work unless you did or bought the wrong thing
Answer:
Windows
Explanation:
It is down to preference. I prefer windows due to its large compatibility with a wide range of apps.
Answer:
Here you go, alter this as you see fit :)
Explanation:
array = []
cnt = 0
while cnt < 11:
x = input("Enter a word: ")
array.append(x)
cnt += 1
y = input("Add another word?(Y/n): ")
if y.lower() == "n":
break
letter = input("\nChoose a letter: ")
if len(letter) != 1:
print("Error: too many characters")
quit()
for n in range(len(array)):
if letter.lower() in array[n].lower():
print(array[n], end= ",")
