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Ulleksa [173]
3 years ago
13

Adam is so good at playing arcade games that he will win at every game he plays. One fine day as he was walking on the street, h

e discovers an arcade store that pays real cash for every game that the player wins - however, the store will only pay out once per game. The store has some games for which they will pay winners, and each game has its own completion time and payout rate. Thrilled at the prospect of earning money for his talent, Adam walked into the store only to realize that the store closes in 2 hours (exactly 120 minutes). Knowing that he cannot play all the games in that time, he decides to pick the games that maximize his earnings
Computers and Technology
1 answer:
klio [65]3 years ago
3 0

Answer:

what the answer chaoices

Explanation:

brainlest me please

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when there is no junk

Explanation:

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According to your course, two benefits of a cloud-based system are_ and_
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Write a program that asks the user to input an integer named numDoubles. Create a dynamic array that can store numDoubles double
Hitman42 [59]

Answer:

Answered in C++

#include <iostream>

using namespace std;

int main() {

   int size;

   cout<<"Length of array: ";

   cin >> size;

   double *numDoubles = new double[size];

   double sum =0;

   cout<<"Array Elements: ";

   for(int i=0;i<size;i++){

       cin>>numDoubles[i];

       sum += numDoubles[i];

   }

   delete [] numDoubles;

   cout<<"Average: "<<sum/size;

   return 0;  

}

Explanation:

This line declares the size (or length) of the array

<em>    int size; </em>

This line prompts the user for the array length

<em>    cout<<"Length of array: "; </em>

This gets the input from the user

<em>    cin >> size; </em>

This dynamically declares the array as of double datatype

<em>    double *numDoubles = new double[size]; </em>

This declares and initializes sum to 0

<em>    double sum =0; </em>

This prompts the user for elements of the array

<em>    cout<<"Array Elements: "; </em>

The following iteration gets input from the user and also calculates the sum of the array elements

<em>    for(int i=0;i<size;i++){ </em>

<em>        cin>>numDoubles[i]; </em>

<em>        sum += numDoubles[i]; </em>

<em>    } </em>

This deletes the array

<em>    delete [] myarray; </em>

This calculates and prints the average of the array

<em>    cout<<"Average: "<<sum/size; </em>

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Answer:

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Printf("\nGreetings %s",name);

}

Explanation:

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