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Goryan [66]
3 years ago
14

(101)² solve it using identities​

Mathematics
1 answer:
almond37 [142]3 years ago
7 0

Answer:

10201

Step-by-step explanation:

=(101)²

=(100+1)²

={100²+2(100)(1)+1²} [(a+b)²=a²+2ab+b²]

=10000+200+1

=10201

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How many times can 8 go into 60
nignag [31]

The correct answers are:

(1) If EXACT number is required, then 7.5.

(2) If multiple of 8 is required then the answer will be 7 times with a remainder of 4.

Explanation:

First you need to express it in the form of equation to make things simpler as follows:

8 * y = 60

We need to find y; to do so, divide 60 by 8:

y = \frac{60}{8}

y = 7.5

Now if you want to find the whole number, then the answer will be 7 times, with 4 left over.

6 0
3 years ago
Read 2 more answers
What is 3x+70=8x-20 show work
Elena-2011 [213]

Answer:

Hi there!

Your answer is:

x= 18

Step-by-step explanation:

3x+70=8x-20

Isolate x on left side

3x+70=8x-20

-8x       -8x

-5x +70 = -20

Isolate whole numbers on right side

-5x +70 = -20

      -70      -70

-5x = -90

Isolate x by dividing both sides by -5

-5x = -90

/-5

x= 18

6 0
3 years ago
Write a how many units in 1 group word Problem for 4 divided by 2/3
Nastasia [14]

       

\displaystyle\bf\\4:\frac{2}{3}=4\times\frac{3}{2}=\frac{4\times3}{2}=2\times3=6



4 0
3 years ago
1 point) Are the functions f,g, and h given below linearly independent? f(x)=e3x+cos(5x), g(x)=e3x−cos(5x), h(x)=cos(5x). If the
Fynjy0 [20]

Answer:

Functions are linearly dependent (are not linearly independent.)

Step-by-step explanation:

Remember that two functions f(x), g(x) and h(x) are said linearly independent on an interval I if the <em>only solution</em> to the equation

\alpha f(x)+\beta g(x)+\omega h(x)=0, \ \text{for all } x\in I

is the trivial one: α = 0, β = 0, ω = 0. If they are not linearly independent, they are called linearly dependent.

Now, let f(x), g(x) and h(x) be the functions:

f(x)=e^{3x}+\cos(5x),

g(x)=e^{3x}-\cos(5x),

h(x)=\cos(5x).

Then, letting α = 1, β= -1 and ω = -2, we see that:

\alpha f(x)+\beta g(x)+ \omega h(x)=e^{3x}+\cos(5x)-e^{3x}+\cos(5x)+2\cos(5x)=0.

Hence, the functions f(x), g(x) and h(x) are not linearly independent, or equivalently, are linearly dependent.

8 0
3 years ago
Find the exponential function that satisfies the given conditions: Initial value = 70, decreasing at a rate of 0.43% per week
dimulka [17.4K]
That'd be y = 70* (1-.00043)^t, where the rate of decrease is really 0.43% and t denotes the # of weeks.  

This simplifies to y = 70*(0.00057)^t. 
                                 
4 0
3 years ago
Read 2 more answers
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