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SpyIntel [72]
3 years ago
14

50 POINTS PLEASE HELP! In order to rewrite log9 (6/5) as log9 (6) - log9 (5) , which of the following is used?

Mathematics
2 answers:
finlep [7]3 years ago
4 0

Answer:

1

Step-by-step explanation:

Anna11 [10]3 years ago
3 0
B. Is the correct answer.
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Help me! Answer in pic not correct !
sladkih [1.3K]

Answer:

Q'=(4,1)\\R'=(6,-5)\\S'=(3,-4)\\T'=(1,-1)

Step-by-step explanation:

First we have to find the coordinates of the original ordered pairs then we will do the translation.

Q=(1,3)\\R=(3,-3)\\S=(0,-2)\\T=(-2,1)

Now we will add 3 to every x value and add a -2 to every y value.

Q=(1_{+3},3_{+(-2)})\\R=(3_{+3},-3_{+(-2)})\\S=(0_{+3},-2_{+(-2)})\\T=(-2_{+3},1_{+(-2)})

When you do that you will get the new prime points.

Q'=(4,1)\\R'=(6,-5)\\S'=(3,-4)\\T'=(1,-1)

8 0
3 years ago
3. At the beginning of the day, a water tank contained 526.8 gallons of water. During the day,
Andru [333]

Answer:

208.85

Step-by-step explanation:

It is 208.85 because when you have .8 + .05 =.85

5 0
3 years ago
Read 2 more answers
4. Line t and AECA and AFDB are shown on the coordinate plane
julia-pushkina [17]

Answer:

A, B, C, E

Step-by-step explanation:

It can be seen from the figure that the points A, B, C and D, all are lying in the line t.

=> So that it can be concluded that AC and BC and BD have the slopes which are equal to each other and also equal to the slop of line t

So that all answer A, B, C are true.

In addition, as FD is parallel with x - axis, so that slope of the line t is equal to <em>tan angel FDB </em>

As FDB is the right triangle with BFD = 90°

=> tan angel FDB = FB/ FD (tan of an acute angel in the right triangle = opposite side/ adjacent side)

=> Slope of the line t is equal to FB/ FD

=> Answer E is true

6 0
3 years ago
Read 2 more answers
The computers of nine engineers at a certain company are to be replaced. Four of the engineers have selected laptops and the oth
Gala2k [10]

Answer:

(a) There are 70 different ways set up 4 computers out of 8.

(b) The probability that exactly three of the selected computers are desktops is 0.305.

(c) The probability that at least three of the selected computers are desktops is 0.401.

Step-by-step explanation:

Of the 9 new computers 4 are laptops and 5 are desktop.

Let X = a laptop is selected and Y = a desktop is selected.

The probability of selecting a laptop is = P(Laptop) = p_{X} = \frac{4}{9}

The probability of selecting a desktop is = P(Desktop) = p_{Y} = \frac{5}{9}

Then both X and Y follows Binomial distribution.

X\sim Bin(9, \frac{4}{9})\\ Y\sim Bin(9, \frac{5}{9})

The probability function of a binomial distribution is:

P(U=k)={n\choose k}\times(p)^{k}\times (1-p)^{n-k}

(a)

Combination is used to determine the number of ways to select <em>k</em> objects from <em>n</em> distinct objects without replacement.

It is denotes as: {n\choose k}=\frac{n!}{k!(n-k)!}

In this case 4 computers are to selected of 8 to be set up. Since there cannot be replacement, i.e. we cannot set up one computer twice or thrice, use combinations to determine the number of ways to set up 4 computers of 8.

The number of ways to set up 4 computers of 8 is:

{8\choose 4}=\frac{8!}{4!(8-4)!}\\=\frac{8!}{4!\times 4!} \\=70

Thus, there are 70 different ways set up 4 computers out of 8.

(b)

It is provided that 4 computers are randomly selected.

Compute the probability that exactly 3 of the 4 computers selected are desktops as follows:

P(Y=3)={4\choose 3}\times(\frac{5}{9})^{3}\times (1-\frac{5}{9})^{4-3}\\=4\times\frac{125}{729}\times\frac{4}{9}\\  =0.304832\\\approx0.305

Thus, the probability that exactly three of the selected computers are desktops is 0.305.

(c)

Compute the probability that of the 4 computers selected at least 3 are desktops as follows:

P(Y\geq 3)=1-P(Y

Thus, the probability that at least three of the selected computers are desktops is 0.401.

6 0
3 years ago
Find the sum to n terms of the series 0.6+0.66+0.666+.....................
RSB [31]
<span>We have
</span>0.6+0.66+0.666+0.6666

Let's take 6 out from the series
6(0.1+0.11+0.111+0.1111+....

<span>Now multiply and divide by 9
</span>\frac{6}{9}(0.9+0.99+0.999+0.9999+....

\frac{6}{9}(1-0.1+1-0.01+1-0.001+1-0.0001+....&#10;\\&#10;\\\frac{6}{9}(1-10^{-1}+1-10^{-2}+1-10^{-3}+...

<span>all 1s add up to n
</span>\frac{6}{9}(n-\frac{1}{10}\times \frac{1-(\frac{1}{10})^{n+1}}{1-\frac{1}{10}})

8 0
3 years ago
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