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2 years ago

Please Help I’ll give brainliest and look at photo for question

Advanced Placement (AP)

2 answers:

max2010maxim [7]2 years ago

5 0

MRNA is the correct answer

stepan [7]2 years ago

4 0

I believe it’s mRNA.

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My coworker wants me to take her on a date should I?

shutvik [7]

Answer:

no unless u want that rona

Explanation:

its probably a kidnapper in a- agh nvm

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2 years ago

I need help with 63!!!! I’ll give beainliest if you can get it right!!! I included 61 to help with it!!

Serggg [28]

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2 years ago

In Africa, parasitic diseases such as malaria are most likely to occur and spread in __________ regions near the Equator.

AVprozaik [17]

Answer:

Tropical or warmer

Explanation:

The warmth and humidity in tropical regions, like near the equator, allow parasitic diseases to thrive among the immense insect population and rich, fertile soils.

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2 years ago

Read 2 more answers

For time t≥0 , the acceleration of an object moving in a straight line is given by a(t)=sin(t23). what is the net change in velo

Firlakuza [10]

The net change in velocity during the given time interval is equal to -0.665.

<u>Given the following data:</u>

Initial time = 0.75 seconds.

Final time = 2.25 seconds.

Acceleration, $a(t) = sin(\frac{t^2}{3} )$

<h3>How to calculate the net change in velocity.</h3>

Since acceleration is the rate of change of velocity of an object, we would derive an expression for the velocity by differentiating with respect to time:

$V(t) = \frac{d}{dt} a(t)\\\\V(t) = \frac{d}{dt} (sin(\frac{t^2}{3} ))\\\\V(t) = cos( \frac{t^2}{3})(\frac{2t}{3})\\\\V(t) = \frac{2t}{3}cos( \frac{t^2}{3})$

Substituting the time interval, we have:

$V(t) = \frac{2\times 2.25}{3}cos( \frac{2.25^2}{3})- \frac{2\times 0.75}{3}cos( \frac{0.75^2}{3})\\\\V(t) = \frac{4.5}{3}cos( \frac{5.0625}{3})- \frac{1.5}{3}cos( \frac{0.5625}{3})\\\\V(t) =1.5(-0.11643)-0.5(0.98247)$

V(t) = -0.665.

Read more on acceleration here: brainly.com/question/24728358

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1 year ago

The graph of f(x) = 1/x cos

nikitadnepr [17]

Answer:

D. f(x) exist for all real numbers where x ≤ -1 or x ≥ 1

Explanation:

You can't divide by 0 and

You can't have a negative squareroot.

So solve for when x=0 for the denominator,

and when is x<0 for the squareroot.

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2 years ago