Answer:
In the long run if one day is rainy there is frequency of 2/5 that other two days will also be rainy.
Step-by-step explanation:
A matrix is formed to classify the weather conditions. It is given that if one day is sunny then there is likely chance that the next day will be cloudy, but if one day is rainy then there is 60% chance that next day will be same. To identify the possibility of next two days we create probability matrix;
Probability (P) = ![\left[\begin{array}{ccc}0&\frac{1}{2} &\frac{1}{2} \\\frac{1}{4} &\frac{1}{2} &\frac{1}{4} \\\frac{1}{4} &\frac{1}{4} &\frac{1}{2} \end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%26%5Cfrac%7B1%7D%7B2%7D%20%26%5Cfrac%7B1%7D%7B2%7D%20%5C%5C%5Cfrac%7B1%7D%7B4%7D%20%26%5Cfrac%7B1%7D%7B2%7D%20%26%5Cfrac%7B1%7D%7B4%7D%20%5C%5C%5Cfrac%7B1%7D%7B4%7D%20%26%5Cfrac%7B1%7D%7B4%7D%20%26%5Cfrac%7B1%7D%7B2%7D%20%5Cend%7Barray%7D%5Cright%5D)
After solving for probability we get a fraction of 2/5
Answer:
Ingresos
Reconocido. $ 19.000. Cuentas por cobrar. 3.000. Gastos incurridos. 7.250. Cuentas por pagar (relacionadas con gastos) 750. Suministros comprados en efectivo.
Step-by-step explanation:
Answer:
Part A
a·(a² - a + 1) + 5·a = a³ - a² + 6·a
Part B
The value of a·(a² - a + 1) + 5·a, for a = -2 is -24
Step-by-step explanation:
Part A
The given function is a·(a² - a + 1) + 5·a
The function is simplified by expanding the product of sums into sums of products, as follows;
a·(a² - a + 1) + 5·a = a × a² - a × a + a × 1 + 5·a = a³ - a² + a + 5·a = a³ - a² + 6·a
The function, a·(a² - a + 1) + 5·a, in simplified format is therefore;
a·(a² - a + 1) + 5·a = a³ - a² + 6·a
Part B
When a = -2, we get;
(a³ - a² + 6·a)
= (-2)³ - (-2)² + 6·(-2) = -8 - 4 - 12 = -24
Answer:
what's your question? I'm here to help if I can.
Answer:
- 15 - 7 (Parentheses)
- 3² (Exponents)
- 8 × 2 (Multiplication)
- 40 ÷ 8 (Division)
- 5 + 9 (Addition starting from the leftmost)
- 14 + 16 (Addition after the first addition operation)
Concept:
When encountering questions that ask for simplifying expressions through operation, following the PEMDAS method would be easier:
- <u>P</u>arentheses
- <u>E</u>xponents
- <u>M</u>ultiplication
- <u>D</u>ivision
- <u>A</u>ddition
- <u>S</u>ubtraction
Therefore, the whole process of simplifying the given expression should follow the PEMDAS method. <u>For extra</u>, whenever there are two occurences of the same operation, then prioritize the leftmost and go right.
Hope this helps!! :)
Please let me know if you have any questions or need further explanation
