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3 years ago

How to solve for area of triangle where A=67 degrees, b=11yd, and c=24yd

Mathematics

1 answer:

skad [1K]3 years ago

4 0

Use the formula of an area of a tringle:

$A=\dfrac{1}{2}bc\sin A$

We have b = 11 yd, c = 24 yd and m∠A = 67°

$A=\dfrac{1}{2}(11)(24)\sin67^o$

$\sin67^o\approx0.9205\\\A=(11)(12)(0.9205)=121.506\ yd^2$

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3 years ago

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saveliy_v [14]

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Step-by-step explanation:

45, 33, 22, 12,

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45-33 = 12

33-22=11

22-12=10

pattern = decreases by one so

12- 9 = 3

3- 8 = -5

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3 years ago