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satela [25.4K]
3 years ago
9

How to solve for area of triangle where A=67 degrees, b=11yd, and c=24yd

Mathematics
1 answer:
skad [1K]3 years ago
4 0

Use the formula of an area of a tringle:

A=\dfrac{1}{2}bc\sin A

We have b = 11 yd, c = 24 yd and m∠A = 67°

A=\dfrac{1}{2}(11)(24)\sin67^o

\sin67^o\approx0.9205\\\A=(11)(12)(0.9205)=121.506\ yd^2

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5 0
3 years ago
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((-2^2)(-1^-3))•((-2^-3)(-1^5))^-2
Vitek1552 [10]

Answer:

  256

Step-by-step explanation:

A calculator works well for this.

_____

None of the minus signs are subject to the exponents (because they are not in parentheses, as (-1)^5, for example. Since there are an even number of them in the product, their product is +1 and they can be ignored.

1 to any power is still 1, so the factors (1^n) can be ignored.

After you ignore all of the things that can be ignored, your problem simplifies to ...

  (2^2)(2^-3)^-2

The rules of exponents applicable to this are ...

  (a^b)^c = a^(b·c)

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3 0
3 years ago
The body temperatures of a group of healthy adults have a bell-shaped distribution with a mean of 98.35°F and a standard deviati
DochEvi [55]

Answer:

a) 99.97%

b) 65%

Step-by-step explanation:

• 68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ.

• 95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ.

• 99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ.

Mean of 98.35°F and a standard deviation of 0.64°F.

a. What is the approximate percentage of healthy adults with body temperatures within 3 standard deviations of the mean, or between 96.43°F and 100.27°F?

μ - 3σ

98.35 - 3(0.64)

= 96.43°F

μ + 3σ.

98.35 + 3(0.64)

= 100.27°F

The approximate percentage of healthy adults with body temperatures is 99.97%

b. What is the approximate percentage of healthy adults with body temperatures between 97 .71°F and 98.99°F?

within 1 standard deviation from the mean - that means between μ - σ and μ + σ.

μ - σ

98.35 - (0.64)

= 97.71°F

μ + σ.

98.35 + (0.64)

= 98.99°F

Therefore, the approximate percentage of healthy adults with body temperatures between 97.71°F and 98.99°F is 65%

4 0
3 years ago
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vampirchik [111]

Answer:

D

Step-by-step explanation:

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6 0
2 years ago
Whats the equation help pls.
garik1379 [7]

Answer:

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6 0
3 years ago
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