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Mademuasel [1]
3 years ago
6

Could someone please help me on this graph? I'll give the Brainliest to whoever is CORRECT.

Mathematics
1 answer:
AlladinOne [14]3 years ago
4 0
Not sure how to use "the Segment tool"
But here's what I have. It should be a straight line.

Hope this helps.

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What is the next terms in<br> the sequence :5;9;13;17​
gulaghasi [49]

Answer:

21,25,29,33

Step-by-step explanation:

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-7 &lt; b/3 what is the answer
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B > -21 is i think you answer.
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A baseball team had 75 players show up for tryouts last year and this year had 90 players show up for tryouts. Find the percent
BigorU [14]

Answer:

20%

Step-by-step explanation:

Subtract the original number from the new number: 90-75=15

The increase is 15

Now divide the increase by the original number: 15/75=.20

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3 years ago
Use a matrix equation to solve the system of linear equations. left brace Start 2 By 1 Matrix 1st Row 1st Column 2nd Row 1st Col
natali 33 [55]

Answer:

\left[\begin{array}{ccc}3&-1&\\-1&1/2\\\end{array}\right]

Step-by-step explanation:

The matrix system for the linear equations: x + 2y = 8, 2x + 6y = 9

\left[\begin{array}{ccc}1&2&\\2&6\\\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}8\\9\end{array}\right]

To get the coefficient of x and y, the inverse of the first matrix (let the first matrix be A) must be known.

A^{-1} = (1 / determinant of A) x Adjoint of A

the determinant of A = (1 x 6) - (2 x 2) = 6 - 4 = 2

Adjoint of A = \left[\begin{array}{ccc}6&-2&\\-2&1\\\end{array}\right]

A^{-1}= \frac{1}{2} \left[\begin{array}{ccc}6&-2\\-2&1\end{array}\right] = \left[\begin{array}{ccc}3&-1&\\-1&1/2\\\end{array}\right]

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3 years ago
. . . . . . . . . . . . . . . . . . . ________
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cool, how long did it take

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3 years ago
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