X+y=1 If x=0, then y=
1 answer:
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Answer:
A. 3x^2 + 4 = 52
3x^2 = 52 - 4
3x^2 = 48
x^2 = 48/3
x^2 = 16
x =
x = 4
B. x^2 - 121 = 0
x^2 = 121
x =
x = 11
C. (b + 4 )2 = 49
2b + 8 = 49
2b = 49 - 8
2b = 41
b = 41/2
We have two solutions for this problem based on the given equation.
<u><em>Answer #1:</em></u>
<u>If the given equation was:</u>
To solve for f, we would need to isolate the "f" on one side of the equation.
In case of the above equation, we can simply do that by subtracting from both sides of the equation
<u>This would give:</u>
f + -
= 6 -
f = 6 -
<u><em>Answer #2:</em></u>
<u>If the given equation was:</u>
To solve for f, we would still need to isolate the "f" on one side of the equation.
<u>This can be done as follows:</u>
................> multiply both sides by (g)
f + 4 = 6g ................> subtract 4 from both sides of the equation
f + 4 - 4 = 6g - 4
f = 6g - 4
Hope this helps :)