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scZoUnD [109]
3 years ago
14

Name the property of equality that justifies going from the first statement to the second statement.

Mathematics
1 answer:
klemol [59]3 years ago
5 0

The answer would be B

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Alison has 63 books on her bookshelf. If she plans on donating % of her books, how many will Alison have left on her bookshelf?​
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Guys need help its surd one <br><img src="https://tex.z-dn.net/?f=5%20%5Csqrt%7B3%20%5Cdiv%202%20%5Csqrt%7B3%20-%20%20%5Csqrt%7B
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Step-by-step explanation:

\displaystyle \Large \boldsymbol{} 5\cdot  \sqrt{3:2\sqrt{3-\sqrt{2} } }  =\\\\\\ 5\cdot  \sqrt{\frac{3}{2\sqrt{3-\sqrt{2} } } \cdot \frac{2\sqrt{3+\sqrt{2} } }{2\sqrt{3+\sqrt{2} } } } = \\\\\\5\cdot  \sqrt{\frac{6\sqrt{3+\sqrt{2} } }{4\cdot \sqrt{9-2} } }  =5\sqrt{\frac{6\sqrt{3+\sqrt{2} } }{2\sqrt{7} } }

But if the condition would be like this

\displaystyle \Large \boldsymbol{} 5\cdot  \sqrt{3:2\sqrt{3-\boldsymbol2\sqrt{2} } }  =\\\\\\5\cdot \sqrt{\frac{3}{2\cdot \sqrt{\underbrace{2+1-2\sqrt{2} \cdot \sqrt{1} }_{(\sqrt{2} -1)^2} } }} =\\\\\\5\cdot \sqrt{\frac{3}{2\cdot (\sqrt{2}-1) } } } = \\\\\\ 5\cdot  \sqrt{\frac{3}{2(\sqrt{2}-1 )}  \cdot \frac{\sqrt{2} +1}{\sqrt{2}+1 }}   =5 \sqrt{\frac{3}{2(2-1)} }  =\boxed{5\sqrt{1,5} }

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3 years ago
How to factor -5x-30y-50
givi [52]
The answer is -5(x+6y+10)
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It’s 358 ft
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34/67=4.9

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