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Andru [333]
3 years ago
11

Simplify, 3xsqrt-75a

Mathematics
1 answer:
Naily [24]3 years ago
7 0
Here you go! Hopefully it was correct as i used an app called Cymath.Please mark me as Brainliest!

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In an isosceles triangle, the longest side measures c units. The other sides of the triangle measure a units. Which equation can
kotegsom [21]

Answer:

pythagorean theorem formula a²=c²+c²

Step-by-step explanation:

A right triangle is a triangle which has 90 degree angle. In the isosceles triangle, you can obtain the right triangle by dividing the half of its segment (you should be able to get)

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What's slope Line<br> pass through( 14, 4)( 21, 6
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What's slope Line
pass through( 14, 4)( 21, 6 Answer :m=2/7
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<img src="https://tex.z-dn.net/?f=4859%20%5Cdiv%2023" id="TexFormula1" title="4859 \div 23" alt="4859 \div 23" align="absmiddle"
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I need desperate help PLEASE!!!
koban [17]

Answer:

OPTION B

OPTION D

Step-by-step explanation:

An element in the domain should be mapped to exactly one element on the co-domain. Also, every element in the domain should be mapped to an element in the co-domain.

These two conditions are satisfied to call a relation, a function.

Two different elements in the domain can be mapped to the same element in the co-domain. But the same element in the domain cannot be mapped to two different elements in the co-domain.

A) {(3,7), (3,6), (5,4), (4,7)}

Here, the element '3' in the domain is mapped to two elements 7 and 6. So, it is not a function.

B) {(1,5), (3,5), (4, 6), (6,4)}

This is a function because all the elements in the domain have a unique image in the co-domain. So, this is a function.

C) {(2,3), (4,2), (4,6), (6,4)}

Here, the element '4' in the domain is again mapped to two different elements. Hence, it cannot be a function.

D) {(0,4), (3,2), (4,2), (6,5)}

This is again a function. Because the domain is mapped to unique elements. So, this is a function.

4 0
3 years ago
Sven starts walking due south at 6 feet per second from a point 140 feet north of an intersection. At the same time Rudyard star
Vsevolod [243]

Answer:

a) y= y₀+vy*t , x= x₀+vx*t

b) they are closest at t= 29.23 s

c) r min = 63.79 ft

Step-by-step explanation:

a) denoting v as velocities and "₀" as initial conditions , then the position of Sven is given by the coordinate (0,y) where

y= y₀+vy*t

and the position of Rudyard is given by the coordinate (x,0) where

x= x₀+vx*t

b) the distance r between Sven and Rudyard  is given by

r²=x²+y²

the distance will be minimum when the derivative of r with respect to the time is 0 . Then taking the derivative of the equation above

2*r*dr/dt = 2*x*dx/dt + 2*y*dy/dt

since dx/dt= vx and dy/dt= vy , then

r*dr/dt = x*vx+ y*vy

dr/dt = (x*vx+ y*vy)/r

assuming that r cannot be 0 , then

dr/dt =0 → x*vx+ y*vy = 0

(x₀+vx*t)*vx + (y₀+vy*t)*vy = 0

-(x₀*vx + y₀*vy) = (vx²+vy²)*t

t= -(x₀*vx + y₀*vy)/(vx²+vy²)

replacing values

t= -(x₀*vx + y₀*vy)/(vx²+vy²) = -[ 140 ft*(-6ft/s) + (-170 ft)*4 ft/s]/[ (-6ft/s)²+ (4 ft/s)²] = 29.23 s

then they are closest at t= 29.23 s

and the minimum distance will be

x = x₀ + vx*t = 140 ft+(-6ft/s)*29.23 s = -35.38 ft

y= y₀+vy*t = (-170 ft)+ 4 ft/s*29.23 s = -53.08 ft

r min = √(x²+y²)= 63.79 ft

r min = 63.79 ft

Note

to prove our assumption that r is not 0 , then x and y should be 0 at the same time. thus

0= y₀+vy*t → t = (-y₀)/vy = -140 ft/(-6ft/s) = 26.33 s

0= x₀+vx*t → t= (-x₀)/vx = -(-170 ft)/4 ft/s = 42.5 s

then r is never 0

8 0
3 years ago
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