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cluponka [151]
3 years ago
14

Which pair of events is dependent? You get a head and a tail in two coin tosses with two different coins. You get a head and a t

ail in two coin tosses using the same coin twice. You pick two numbered billiard balls from a bag of balls one after the other without replacement. You draw two red cards one after the other with replacement.
Mathematics
1 answer:
brilliants [131]3 years ago
6 0
The billiard balls without replacement.

Let's say there are 10 billiard balls 5 red and 5 blue.
If you pick a blue ball on the first pick you had a 5/10 chance
Now your chances of getting a red are only 5/9.
What happened on the first pick affects what happens on the second (making it dependent)
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Integrate Sec (4x - 1) Tan (4x - 1) Dx ​
Delicious77 [7]

\bf \displaystyle\int~sec(4x-1)tan(4x-1)dx \\\\[-0.35em] ~\dotfill\\\\ sec(4x-1)tan(4x-1)\implies \cfrac{1}{cos(4x-1)}\cdot \cfrac{sin(4x-1)}{cos(4x-1)}\implies \cfrac{sin(4x-1)}{cos^2(4x-1)} \\\\[-0.35em] ~\dotfill\\\\ \displaystyle\int~\cfrac{sin(4x-1)}{cos^2(4x-1)}dx \\\\[-0.35em] ~\dotfill\\\\ u=cos(4x-1)\implies \cfrac{du}{dx}=-sin(4x-1)\cdot 4\implies \cfrac{du}{-4sin(4x-1)}=dx \\\\[-0.35em] ~\dotfill

\bf \displaystyle\int~\cfrac{~~\begin{matrix} sin(4x-1) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }{u^2}\cdot \cfrac{du}{-4~~\begin{matrix} sin(4x-1) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\implies -\cfrac{1}{4}\int\cfrac{1}{u^2}du\implies -\cfrac{1}{4}\int u^{-2}du \\\\\\ -\cfrac{1}{4}\cdot \cfrac{u^{-2+1}}{-1}\implies \cfrac{1}{4}\cdot u^{-1}\implies \cfrac{1}{4u}\implies \cfrac{1}{4cos(4x+1)}+C

5 0
3 years ago
I need help with number 5 ASAPPPPP!!!!!!
kogti [31]
It is d- the function is a line
3 0
2 years ago
Write the solution in interval notation {x| 3 less than or equal to x}
klemol [59]

Answer:

Set in Interval Notation is:  [ 3, ∞)

Step-by-step explanation:

Here, the given expression is:

R  =  {x| 3 less than or equal to x}

Here, the given set is given in the ROSTER FORM of set.

Now, converting the statement in mathematical form, we get:

R  = { x : 3 ≤ x}

So, here: R is the SET OF AL ELEMENTS SUCH THAT each element is either EQUAL TO 3, or GREATER THAN 3.

Writing the st in SET BUILDER FORM, we get:

R = { 3, 4, 5, 6, ....... }

So, R in Interval Notation is:  [ 3, ∞)

4 0
3 years ago
Read 2 more answers
Which is the correct answers? (more than one)
viktelen [127]

B True because both graphs approaches x=0 but never touches it

E True if you just graph it out you can see that graph of g is going down and the graph of x is going up

A false because neither of the equations have a y intercept they have asymptote of x=0

C false because it is also a reflection across the x axis

D incorrect is because they both have domain {0<x<♾}

Hope this helped!

6 0
3 years ago
Zeno is walking in a straight line. With each step, he covers half the remaining distance between him and the end of his path, w
shtirl [24]
8 foot path

1st step = 8/2 = 4ft
2nd step = 4/2 = 2ft
3rd step = 2/2 = 1ft
4th step = 1/2 = 1/2ft

So he covered 7 1/2 ft (or 7.5ft)
5 0
3 years ago
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