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ValentinkaMS [17]
3 years ago
7

Sandra scores 12 out of 30 in her maths test. Write this as a fraction in its simplest form.​

Mathematics
1 answer:
Andrew [12]3 years ago
8 0

Step-by-step explanation:

12/30

find highest common factor; 6

divide both sides by 6

(12/6) (30/6)

2/5

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]Triangle R Q S is cut by line segment T V. Line segment T V goes from side Q R to side R S. The length of R V is x + 10, the le
Murrr4er [49]

The value of 'x' that would make Line segment T V is parallel to Line segment Q S is 10. Option C

<h3>How to determine the value</h3>

It is important to note that for line TV to be parallel to line QS, the sides of the triangle must be divided equally.

Thus, we have

RT/TQ = RV/VS

RT = x + 10

TQ = x - 3

RV = x + 10

VS = x

Substitute the value

\frac{x + 4}{x-3} = \frac{x + 10}{x}
Cross multiply

(x+ 4) × x = (x + 10) × (x-3)

x² + 4x =  x² -3x + 10x -30

Divide through by x²

4x = -3x + 10x - 30

Collect like terms

4x + 3x - 10x = - 30

-3x = -30

x = -30/ -3

x = 10

Thus, the value of 'x' that would make Line segment T V is parallel to Line segment Q S is 10 Option C

Learn more about triangles here:

https://brainly.in/question/1399334

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4 0
2 years ago
Please help me! :( <br> I don’t understand
vovangra [49]

Answer:

the answer is 1.25

Step-by-step explanation:

you need to divide the y axis by the x axis for example

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6 0
4 years ago
Y= 30x + 10 how do you graph this equation?​
Lapatulllka [165]

Answer:

sdfg

Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 4.4 parts
Komok [63]

Solution:

To test the hypothesis is that the mean ozone level is different from 4.40 parts per million at 1% of significance level.

The null hypothesis and the alternative hypothesis is :

$H_0: \mu = 4.40$

$H_a: \mu \neq 4.40$

The z-test statistics is :

$z=\frac{\overline x - \mu}{\left( \sigma / \sqrt n \right)} $

$z=\frac{4.2 - 4.4}{\left(0.7 / \sqrt{23} \right)}  $

$z =\frac{-0.2}{0.145}$

z = -1.37

The z critical value for the two tailed test at 99% confidence level is from the standard normal table, he z critical value for a two tailed at 99% confidence is 2.57

So the z critical value for a two tailed test at 99% confidence is ± 2.57

Conclusion :

The z values corresponding to the sample statistics falls in the critical region, so the null hypothesis is to be rejected at 1% level of significance. There is a sufficient evidence to indicate that the mean ozone level is different from 4.4 parts per million. The result is statistically significant.

4 0
3 years ago
How to do this? And state it cause Idk how
jenyasd209 [6]
12 liters is 5 hours meaning the rate of water dripping is 2.4:1 or 2.4 liters every hour
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3 years ago
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