Pls help, i need this in 5 mins!

Help I’ll give brainliest pls don’t answer if you don’t know

zysi [14]

Answer:

You have to do 2*6-1 which is 11. Then z times 11, which would be 1*11= 11.

So answer's 11

Step-by-step explanation:

6 0

3 years ago

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Change the given equation to Slope-Intercept Form of a Linear Equation. 3x – 7y = 35

denis-greek [22]

slope-intercept form is y = mx + b

3x - 7y = 35
 -3x -3x
 -7y = -3x + 35 (divide each side by -7)

y = -3/-7x + 35/-7

y = 3/7x - 5

6 0

3 years ago

When x=5 and y=2 (x-y)^2

GrogVix [38]

Answer:

9

Step-by-step explanation:

new formula : (5 - 2) ^2

So 5- 2 equals 3. And 3 to the second power is 9

7 0

3 years ago

Q1:The number of students in a chess club decreased from 23 to 13. What is the percent decrease? Round your answer to the neares

nataly862011 [7]

Answer:

Step-by-step explanation:

23 x .565 = 12.995

12.995 rounded is 13.

So if the answer is .565, and you need to round to the nearest percent, it would be 57%.

5 0

3 years ago

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The price of products may increase due to inflation and decrease due to depreciation. Marco is studying the change in the price

inn [45]

Answer:

Product A has a greater percentage change in price.

Step-by-step explanation:

Part A:

The price f product A, f (x) after x years is given by:

$f(x) = 0.69\cdot(1.03)^{x}$

After x = 0 years, the price of product A is:

$f(0) = 0.69\cdot(1.03)^{0}=0.69$

After x = 1 years, the price of product A is:

$f(1) = 0.69\cdot(1.03)^{1}=0.69\cdot (1+0.03)=0.69\cdot (1+3\%)$

After 1 year, the price of product A is 3% times more than the original price.

This means that after one year, the new price is 103% of the original price, which means the price product A is increasing by 3%.

Again after x = 2 years, the price of product A is:

$f(2) = 0.69\cdot(1.03)^{2}=[0.69\cdot (1+3\%)]\times (1.03)$

This implies that after 2 years, the price of product A is 103% of the price after year 1.

This implies that the price of product A is 3% more than the previous year.

Thus, the price of product A is increasing each year by 3%.

Part B:

The data for Product B is as follows:

Time (t) Price [f (t)]

1 10,100

2 10,201

3 10,303.01

4 10,406.04

Product B is clearly increasing in price.

Consider the changes in price of Product B in the following intervals of years:

Year 1 - Year 2:

Price in year 1 = $10,100

Price in Year 2 = $10,201

Compute the increase percentage as follows:

$\text{Increase}\%=\frac{10201-10100}{10100}=0.01=1\%$

Year 2 - Year 3:

Price in Year 2 = $10,201

Price in year 3 = $10,303.01

Compute the increase percentage as follows:

$\text{Increase}\%=\frac{10303.01-10201}{10201}=0.01=1\%$

Year 3 - Year 4

Price in year 3 = $10,303.01

Price in Year 4 = $10,406.04

Compute the increase percentage as follows:

$\text{Increase}\%=\frac{10,406.04-10303.01}{10303.01}=0.09999\approx 0.01=1\%$

It is quite clear that the price of product B increases by 1% each year.

Thus, Product A has a greater percentage change in price.

3 0

3 years ago