Answer:
Step-by-step explanation:
To prove Δ ABC similar to ΔDBE we can consider
Segments AC and DE are parallel.
⇒ DE intersects AB and BC in same ratio.
AB is a transversal line passing AC and DE.
⇒∠BAC=∠BDE [corresponding angles]
Angle B is congruent to itself due to the reflexive property.
All of them are telling a relation of parts of ΔABC to ΔDBE.
The only option which is not used to prove that ΔABC is similar to ΔDBE is the first option ,"The sum of angles A and B are supplementary to angle C".
Answer:
Draw it with 9 cm for length and width.
Step-by-step explanation:
The product is the maximum area when the length and width are as close as possible, or equal to each other. Because length and width are 2 sides each, we can divide 36 by 4, which is 9.
9x9 = 81 cm^2. This is the largest area possible.
So first factor it
1008=2*2*2*2*3*3*7
group them in similar pairs
1008=(2*2)(2*2)(3*3)*7
now remember we can do
so
=
2*2*3*
=
12√7
the answer is B
Step-by-step explanation:
11) x^5
12) 5x^2
13) x+21
14) 2x-8
15) 3^3
=3*3*3
=27
16)2^5
=2*2*2*2*2
=32
17) 5^4
=5*5*5*5
=625
18)2 times a number p squared
19)3 times a number m fifth power
20)the addition of half a number and 2
T-2(3-2t)=2t+9
t-6+4t=2t+9
5t-6=2t+9
5t-2t=9+6
3t=15
t=15/3
t=5
