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Burka [1]
3 years ago
8

Suppose that a and b are integers, a ≡ 4 (mod 13), and b ≡ 9 (mod 13). find the integer c with 0 ≤ c ≤ 12 such that

Mathematics
1 answer:
alisha [4.7K]3 years ago
5 0
The answer is B hope this helped
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Avaluate 2^3x-1 for x=1
DENIUS [597]

<em><u>Answer:</u></em>

4 or 7 (Check the explanation to see which one your equation <em>actually</em> is.

<em><u>Step-by-step explanation:</u></em>

One thing I want to clarify for you, It's Evaluate, not Avaluate.

Okay so, we want to find the value of 2^3x-1 and we know x = 1.

You didn't really clarify if the expression was 2^{3x-1} or 2^{3x}-1, so I'll be doing both:

For 2^{3x-1}, we should plug in x to get 2^{3(1)-1} and then simplify to get 2^{2}.

2 to the power of 2 or 2^{2} is equal to 2 * 2 or 4.

The second one, 2^{3x}-1, we should plug in x to get 2^{3(1)}-1 and then to become 2^{3}-1. 2 to the power of 3 or 2^{3} is 8 and then minus 1 is 7.

7 0
3 years ago
Read 2 more answers
Solve this and show work​
just olya [345]

Answer:

1.71

Step-by-step explanation:

x/4 = 3/7

4 * 3 = 12

12/7 = 1.714285714285714

Rounded to the nearest hundreths, the answer is  1.71

6 0
3 years ago
A bag contains 7 blue cards, 4 green cards, 6 red cards, and 8 yellow cards. You randomly choose a card. How many possible outco
Digiron [165]

It is given that the bag contains 7 blue cards, 4 green cards, 6 red cards, and 8 yellow cards. Thus, there are four colors of cards. So, in randomly a card there are just four possible outcomes. The outcomes are:

1. A Blue Card

2. A Green Card

3. A Red Card

4. A Yellow Card

Their probabilities of occurrence will differ but it is a fact that there will be just four possible outcomes.

5 0
3 years ago
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(13 less than a)<br> How would this be solved in algebraic expression
Delicious77 [7]

Answer:

<em>a </em>- 13

Step-by-step explanation:

a- 13 because you are taking 13 away from a

8 0
3 years ago
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I’ll give the Brainliest!!!
Varvara68 [4.7K]
It’s B hope this helps
7 0
3 years ago
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