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Mademuasel [1]
3 years ago
5

100 POINTS AND BRAINLIEST! SUPPER EASY IM JUST DU.MB!

Mathematics
2 answers:
NikAS [45]3 years ago
7 0

"inspiring that a person can say we own ourselves and no other person does"

Step-by-step explanation:

Svet_ta [14]3 years ago
4 0

Answer:

7hrs late but uhm

Locke is relating to slavery, specifically saying it isn’t right to own someone else or like control them.

Step-by-step explanation:

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In order for smallest to largest is 70% 2/3, 0.62,13/20,0.6
likoan [24]

Answer:

70% = 0.70

2/3 = 0.667

0.62

13/20 = 0.65

0.6 = 0.60

0.6 < 0.62 < 13/20 < 2/3 < 70%

8 0
3 years ago
Amanda recorded the temperatures at which two oils freeze:
lianna [129]

Answer:

Peanut oil freezes at a higher temperature than olive oil because 3.1 °C > –6.1 °C.

Step-by-step explanation:

Well since 3.1 is greater than -6.1 then it should be Peanut oil freezes at a high temperature. I did the test and I got it right. I hope you do to. :)

4 0
3 years ago
Solve the equation above for X.
SpyIntel [72]

Answer:

444

Step-by-step explanation:

add 41 to both sides and then divide 1/2 on each side

7 0
3 years ago
How do you convert from Celsius to Fahrenheit temperatures?
bekas [8.4K]

Answer:

c

Step-by-step explanation:

you would multiply the number by x/frac(9/5) then add 32

6 0
2 years ago
Brandon is on one side of a river that is 50 m wide and wants to reach a point 300 m downstream on the opposite side as quickly
AlexFokin [52]
Let P be Brandon's starting point and Q be the point directly across the river from P. 
<span>Now let R be the point where Brandon swims to on the opposite shore, and let </span>
<span>QR = x. Then he will swim a distance of sqrt(50^2 + x^2) meters and then run </span>
<span>a distance of (300 - x) meters. Since time = distance/speed, the time of travel T is </span>

<span>T = (1/2)*sqrt(2500 + x^2) + (1/6)*(300 - x). Now differentiate with respect to x: </span>

<span>dT/dx = (1/4)*(2500 + x^2)^(-1/2) *(2x) - (1/6). Now to find the critical points set </span>
<span>dT/dx = 0, which will be the case when </span>

<span>(x/2) / sqrt(2500 + x^2) = 1/6 ----> </span>

<span>3x = sqrt(2500 + x^2) ----> </span>

<span>9x^2 = 2500 + x^2 ----> 8x^2 = 2500 ---> x^2 = 625/2 ---> x = (25/2)*sqrt(2) m, </span>

<span>which is about 17.7 m downstream from Q. </span>

<span>Now d/dx(dT/dx) = 1250/(2500 + x^2) > 0 for x = 17.7, so by the second derivative </span>
<span>test the time of travel, T, is minimized at x = (25/2)*sqrt(2) m. So to find the </span>
<span>minimum travel time just plug this value of x into to equation for T: </span>

<span>T(x) = (1/2)*sqrt(2500 + x^2) + (1/6)*(300 - x) ----> </span>

<span>T((25/2)*sqrt(2)) = (1/2)*(sqrt(2500 + (625/2)) + (1/6)*(300 - (25/2)*sqrt(2)) = 73.57 s.</span><span>
</span><span>
</span><span>
</span><span>
</span><span>mind blown</span>
8 0
3 years ago
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