Let's take a look at D:
<span>D) y = (x-1)^2 - 16 Compare this to
y = (x-h)^2 + k This is the std. equation of a parabola in vertex form.
You can see, by comparison, that h=1 and k= -16; these are the coordinates of the vertex, clearly shown in the diagram.
Since the coefficient of (x-h)^2 is +1, the graph opens upward (which the given graph confirms), and is neither compressed nor stretched vertically.</span>
The slope of a line is calculated by dividing the one y portion of the line by one x portion of the line. In this problem we have two points which can indicate us one portion of the y axis and one portion of the x axis. If we have two points of one line, then we can calculate its slope:
Point one (x1, y1)
Point two (x2, y2)
then the slope can be calculated as:
m = (y2 - y1)/(x2 - x1)
So lets use our data:
Point one (2, 10)
Point two (5, 8)
then the slope can be calculated as:
m = (8 - 10)/(5 - 2<span>)
</span>m = -2/3
therefore the slope is negative and is -2/3
C) x+3
first one factors to (x+3)(x-3)
second factors to (x+3)(x-2)
