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AfilCa [17]
3 years ago
6

Why is 4320 divisible by 3, 9, and 10

Mathematics
1 answer:
marishachu [46]3 years ago
7 0

Answer:

One integer A is divisible by another integer B,

if after dividing them, A ÷ B, the remainder is zero.

4,320 is divisible by 10, if there is an integer 'n' such that 4,320 = 'n' × 10.

Notice that dividing our numbers leaves no remainder:

4,320 ÷ 10 = 432 + 0;

So, 4,320 = 432 × 10;

=> 4,320 is divisible by 10.

10 is called a divisor (a factor) of 4,320.

10 | 4,320

The shorthand notation A | B means A divides B.

4,320 is a multiple of 10.

Note that this is also the first step of the Euclidean Algorithm, where the division of the numbers stops when a remainder equal to zero is reported.

4,320 is divisible by 10:

10 | 4,320

Step-by-step explanation:

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