Answer: C.
Step-by-step explanation: Plug in x in the formula. Solve for each y by plugging in each x in the formula and seeing if it works. This took me like 3 min to solve
Ok
I=PRT
P=present amount
I=interst
T=time in years
R=rate in percent
when you double your money, interest=present amount
I=1000=P
T=10 years
so
1000=1000(10)(R)
1000=10000R
divide both sides by 10000
0.10=R
10% is answer
Answer:
a. 0.9049
b. 0.2297
c. 0.8473
Step-by-step explanation:
Given U = 46.7, SD = 1.75
and Z = (U - X)/sd
(a). We want to find P(X<=49)
P(X<=49) = P(Z<= 49-46.7/1.75)
= P(Z<= 1.31)
= 0.90490
~= 0.9049
(b) P(X>=48) = P(Z>=48-46.7/1.75)
=P(Z>=0.7429) = 1 - P(Z<=0.7429)
= 1 - 0.77035
= 0.22965
=0.2297
(c) The required probability is given by P(U±2.5).
P(46.7±2.5) = (44.2<= X <=49.2)
= P( 44.2<= Z <= 49.2)
= P(44.2 - 46.7/1.75 <= Z <= 49.2- 46.7/1.75)
= P( - 1.4286 <= Z <= 1.4285)
= P(1.4285) - P(-1.4285)
= P(1.43 ) - P(-1.43)
= 0.92364 - 0.07636
= 0.8473
Answer:
C.
Step-by-step explanation:
Just finished the Unit Test Review on edge2020
Answer:
140 toy cars
Step-by-step explanation:
The ratio of Ed's toy car to Pete's toy car is initially given as 5:2
Ed gave Pete a total number of 30 cars
Let x represent the greatest common factor that exists between both number
Number of Ed's car is represented as 5x
Number of Pete car is represented as 2x
Since they each have an equal number of cars which is 30 then we can solve for x as follows
5x-30=2x+30
Collect the like terms
5x-2x= 30+30
3x= 60
Divide both sides by the coefficient of x which is 3
3x/3=60/3
x=20
Ed's car is 5x, we substitute 20 for x
5(20)
= 100 cars
Pete car is 2x,we substitute 20 for x
2(20)
= 40 cars
Therefore, the total number of cars can be calculated as follows
= 100+40
= 140 toy cars
Hence they have 140 toy cars altogether
