3 years ago

Domain:_ Range:_ Function:___

Mathematics

1 answer:

Scilla [17]3 years ago

8 0

Answer:

Domain: {-4,-2,1,3}

Range: {3,2,-1,-5}

Function: (-4,-5);(-2,-1);(-2,3);(1,2);(3,-1)

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Help please!

Anna71 [15]

Answer:

y= -4x^2 + 15x - 14

Step-by-step explanation:

A parabola is always in the form y = ax^2 + bx + c.

Substitute each point to produce different equations:

-14 = 0a + 0b + c = c

so c = -14

-3 = a1^2 + b1 + c = a + b - 14

so a + b = 11

0 = a2^2 + b2 + c = 4a + 2b -14 = 0

so 4a + 2b = 14

if we double a + b = 11 we get 2a + 2b = 22

Subtract this from 4a + 2b = 14 and we get 2a = -8 so a= -4 and b = 11 - a = 15

We don't need to use the (3,5) points as we have all the information we need.

4 0

3 years ago

Read 2 more answers

Help plz??????????????????????????????

Juliette [100K]

I would go with -15 that’s what I came up with

8 0

4 years ago

What is the equation of a line that contains the point (2,-5) and is parallel to the line y=3x-4

aev [14]

Answer:

$\large\boxed{y=3x-11}$

Step-by-step explanation:

$\text{Let}\\\\k:y=m_1x+b_1\\\\l:y=m_2x+b_2\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\l\ \parallel\ k\iff m_1=m_2\\\\===================================\\\\y=3x-4\to m_1=3\\\\\text{Therefore}\ m_2=3.\\\\\text{We have the equation:}\ y=3x+b.\\\\\text{Put the coorsdinates of the point (2, -5) to the equation of the line}\\\\-5=3(2)+b\\-5=6+b\qquad\text{subtract 6 from both sides}\\-11=b\to b=-11$