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3 years ago

Factor out the GCF from the terms of the polynomial −2x5 − 6x3 − 16x2.

Mathematics

1 answer:

Ahat [919]3 years ago

4 0

Answer:

2x^2(x^3+3x+8)

Step-by-step explanation:

Factor out the gcf which in this case is -2x^2 because that's the greatest factor all of the terms have in common this results in -2x^2(x^3+3x+8)

Btw the ^ represents the exponent

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Can you guys please help me

ICE Princess25 [194]

9514 1404 393

Answer:

see below

Step-by-step explanation:

Each vertex has a single-letter label.

Each edge joins two vertices, and is named by naming those two vertices.

Each polygon is named by listing the vertices at its corners. It is a plane figure.

The base is the polygon opposite the point where all of the triangles come together.

16. figure: pentagonal pyramid ABCDEF

17. base: ABCDE

18. faces: ABF, BCF, CDF, DEF, AEF, ABCDE (the bottom face, or base)

19. edges: AB, BC, CD, DE, AE, FA, BF, CF, DF, EF

20. vertices: A, B, C, D, E, F

3 0

2 years ago

The estimated daily living costs for an executive traveling to various major cities follow. The estimates include a single room

Alexandra [31]

Answer:

$\bar x = 260.1615$

$\sigma = 70.69$

The confidence interval of standard deviation is: $53.76$ to $103.25$

Step-by-step explanation:

Given

$n =20$

See attachment for the formatted data

Solving (a): The mean

This is calculated as:

$\bar x = \frac{\sum x}{n}$

So, we have:

$\bar x = \frac{242.87 +212.00 +260.93 +284.08 +194.19 +139.16 +260.76 +436.72 +355.36 +.....+250.61}{20}$

$\bar x = \frac{5203.23}{20}$

$\bar x = 260.1615$

$\bar x = 260.16$

Solving (b): The standard deviation

This is calculated as:

$\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n-1}}$

$\sigma = \sqrt{\frac{(242.87 - 260.1615)^2 +(212.00- 260.1615)^2+(260.93- 260.1615)^2+(284.08- 260.1615)^2+.....+(250.61- 260.1615)^2}{20 - 1}}$ $\sigma = \sqrt{\frac{94938.80}{19}}$

$\sigma = \sqrt{4996.78}$

$\sigma = 70.69$ --- approximated

Solving (c): 95% confidence interval of standard deviation

We have:

$c =0.95$

So:

$\alpha = 1 -c$

$\alpha = 1 -0.95$

$\alpha = 0.05$

Calculate the degree of freedom (df)

$df = n -1$

$df = 20 -1$

$df = 19$

Determine the critical value at row $df = 19$ and columns $\frac{\alpha}{2}$ and $1 -\frac{\alpha}{2}$

So, we have:

$X^2_{0.025} = 32.852$ ---- at $\frac{\alpha}{2}$

$X^2_{0.975} = 8.907$ --- at $1 -\frac{\alpha}{2}$

So, the confidence interval of the standard deviation is:

$\sigma * \sqrt{\frac{n - 1}{X^2_{\alpha/2} }$ to $\sigma * \sqrt{\frac{n - 1}{X^2_{1 -\alpha/2} }$

$70.69 * \sqrt{\frac{20 - 1}{32.852}$ to $70.69 * \sqrt{\frac{20 - 1}{8.907}$

$70.69 * \sqrt{\frac{19}{32.852}$ to $70.69 * \sqrt{\frac{19}{8.907}$

$53.76$ to $103.25$

8 0

2 years ago

The quadratic regression graphed on the coordinate grid represents the height of a road surface x meters from the center of the

andrew-mc [135]

The height of the surface increases, then decreases, from the center out to the sides of the road.

<h3>What is quadratic equation?</h3>

The polynomial having a degree of 2 is defined as the quadratic equation it means that the variable will have a maximum power of 2.

Let

y------> the height of the surface

x------> the road

we know that

The quadratic regression graphed represent a vertical parabola open downward

The function increase in the interval --------> (-5,0)

The function decrease in the interval --------> (0,5)

therefore

The height of the surface increases, then decreases, from the center out to the sides of the road.

To know more about quadratic equation follow

brainly.com/question/1214333

#SPJ1

5 0

2 years ago

Read 2 more answers

Click the picture that I sent you

Digiron [165]

Answer: 1211.6585 years

<u>Step-by-step explanation:</u>

The equation for exponential growth is: $P=P_oe^{kt}$

P: final population
P₀: initial population
k: rate of decay (or growth)
t: time

Use the half life information to find k:

$\dfrac{1}{2}P_o=P_oe^{k(800)}\\\\\\\dfrac{1}{2}=e^{800k}\qquad \rightarrow \qquad \text{divided both sides by}\ P_o\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=800k\qquad \rightarrow \qquad \text{applied ln to both sides}\\\\\\\dfrac{ln(\frac{1}{2})}{800}=k\qquad \rightarrow \qquad \text{divided both sides by 800}\\\\\\\large\boxed{-0.000867=k}$

Next, input the information (65% decayed = 35% remaining) and the k-value to find your answer.

$.35P_o=P_oe^{-0.000867t}\\\\\\.35=e^{-0.000867t}\\\\\\ln(.35)=-0.000867t\\\\\\\dfrac{ln(.35)}{-0.000867}=t\\\\\\\large\boxed{1211.6585=t}$

5 0

3 years ago

I WANT TO KNOW<br> WHAT IS THE MULTIPLE OF 6

Leni [432]

6, 12, 18, 24, 30
Keep plus this number by 6

5 0

2 years ago

Read 2 more answers