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4 years ago

Factor out the GCF from the terms of the polynomial −2x5 − 6x3 − 16x2.

Mathematics

1 answer:

Ahat [919]4 years ago

4 0

Answer:

2x^2(x^3+3x+8)

Step-by-step explanation:

Factor out the gcf which in this case is -2x^2 because that's the greatest factor all of the terms have in common this results in -2x^2(x^3+3x+8)

Btw the ^ represents the exponent

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What is a multiplication problem that would get a product between 1.25 and 1.75

Alex73 [517]

Answer:

1.25 x 1.75

=2.1875

Step-by-step explanation:

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3 years ago

Is the ordered pair (5,2) a solution of the equation f (x) = x - 3?

valentinak56 [21]

Answer:

Yes

Step-by-step explanation:

Step 1: Define

f(x) = x - 3

(5, 2) is equal to x = 5, f(x) = 2

Step 2: Substitute and Evaluate

2 = 5 - 3

2 = 2

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3 years ago

What is the solution of 4 + StartRoot 5 x + 66 EndRoot = x + 10? x = –10 x = 3 x = –10 or x = 3 no solution

irga5000 [103]

This is a question that is not awnsable so your teachers need to get smarter

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3 years ago

In a bag, there are 10 black plastic chips, 7 yellow, 5 red, and 3 green. Two chips are drawn at random with replacement.

Alja [10]

When the black chip is drawn, there is already one less chip in the bag; keep this in mind..

the probability of getting a black chip out of the bag is 10/25 or 2/5

now since there is one less chip, there is a total of 24 chips now..

so now the probability of getting a red chip is 5/24

then you would multiply the two events together and get:

2/5 x 5/24....solve

6 0

3 years ago

A heavy rope, 40 ft long, weighs 0.8 lb/ft and hangs over the edge of a building 110 ft high. How much work is done in pulling t

olya-2409 [2.1K]

Answer:

Therefore the work done is 640 ft pound.

Step-by-step explanation:

Given that, a heavy rope 40 ft long, weighs 0.8 lb/ft.

Force = weight.

Let we pull x ft. Then the remain rope = (40-x)ft.

(40-x) ft it is variable.

The weight of (40-x) ft is =(40-x)0.8 lb

∴ Force =(40-x)0.8 lb

Work done = Force × displacement

= (40-x)0.8 Δx [ displacement = Δx]

Therefore ΔW =(40-x)0.8 Δx

Since total rope is pulling up on the top of the building. Total displacement = 40 ft.

Total work done $=\int_0^{40}(40-x)0.8 dx$

$=[32x-\frac{0.8x^2}{2}]_0^{40}$

$=[(32\times 40)-0.4(40)^2]$

=640 ft pound.

Therefore the work done is 640 ft pound.

7 0

3 years ago