Step-by-step explanation:
you did not show us the picture or described what the shaded area is.
I assume it is the area of the circle without the inner square (as the "rectangke" is actually a square, because its sides are equally long).
so, we need to calculate the area of the circle and subtract the area of the square.
the area of the square is 3×3 = 9 cm².
the area of the circle is
pi×r²
with r being the radius.
so,
pi×4² = pi×16 = 16pi
the shaded area is then
16pi - 9 = 41.26548246... cm² ≈ 41.27 cm²
nothing of the answer options seems to be in that area, so maybe my assumption about the shaded area is wrong. or the specified answer options are mistyped. or both.
anyway, without additional information that is the best I can do.
The area of a trapezoid is calculated using the formula: 1/2(a + b)h. The diagram shows that base number one (a) is 8.5 dm and base number two (b) is 26.5 dm. The height is 9 dm. Substitute these values into the formula.
1/2(8.5 + 26.5) * 9, add 8.5 and 26.5 inside the parentheses.
1/2(35) * 9, you can now solve from left to right. Multiply 1/2 and 35.
17.5 * 9, multiply to get your final answer. The area of the trapezoid is C. 157.5 dm^2.
Hey there! I'm happy to help!
The formula for the perimeter of a rectangle is 2L+2W=P where W is the width and L is the length. This is because we have our two sides that are lengths and our two sides that are widths (different values) and we add them together to see what the distance around the whole rectangle is.
So, let's insert these values into the equation.
2(2x+4)+2(x+8)=96
We use the distributive property to remove the parentheses (which is us multiplying our equations for length and width by two).
4x+8+2x+16=96
We combine the like terms.
6x+24=96
We subtract 24 from both sides.
6x=72
Divide both sides by 6.
x=12
Now that we have our value of x, we can plug it into our length and width equations to find those values.
LENGTH:
2x+4
2(12)+4
24+4
28
WIDTH:
x+8
12+8
20
So, our length is 28 and our width is 20.
Have a wonderful rest of your day and keep on learning! :D
