2 years ago

If h(x)=x²-5x+7, find the value of h(2), and h(-5)

Mathematics

2 answers:

Anni [7]2 years ago

8 0

Answer:

h(2) = $2^{2}$ -5(2)+7 = 1

h(-5) = $(-5)^{2}$ -5(-5)+7 = 7

Step-by-step explanation:

vichka [17]2 years ago

8 0

H(2)= (2)^2 -5(2)+7
2^2 is 4
-5x2 is -10
+7
So 4-10+7
=1
h(2)=1

h(-5)=(-5)^2 -5(-5)+7
-5^2 is 25
-5x-5 is 25
+7
So h(-5)=57

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