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3 years ago

If h(x)=x²-5x+7, find the value of h(2), and h(-5)

Mathematics

2 answers:

Anni [7]3 years ago

8 0

Answer:

h(2) = $2^{2}$ -5(2)+7 = 1

h(-5) = $(-5)^{2}$ -5(-5)+7 = 7

Step-by-step explanation:

vichka [17]3 years ago

8 0

H(2)= (2)^2 -5(2)+7
2^2 is 4
-5x2 is -10
+7
So 4-10+7
=1
h(2)=1

h(-5)=(-5)^2 -5(-5)+7
-5^2 is 25
-5x-5 is 25
+7
So h(-5)=57

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Step-by-step explanation:

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3 years ago

Can someone help me with this?

Anna35 [415]

Answer:

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Series = 2+6+18.......= 2+2•3¹+ 2•3².......= 728

Now,

$Sum = \frac{a( {r}^{n} - 1) }{(r - 1)} \\$

So,

$\frac{a( {r}^{n} - 1)}{(r - 1)} = 728 \\ \frac{2( {3}^{n} - 1) }{(3 - 1)} = 728 \\ \frac{2( {3}^{n} - 1) }{2} = 728 \\ {3}^{n} - 1 = 728 \\ {3}^{n}=728+1\\ {3}^{n} = 729 \\ {3}^{n} = {3}^{6} \\ \boxed{ n = 6}$

Therefore, number of terms is 6

6 is the right answer.

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3 years ago

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Irina18 [472]

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My name is Ann [436]

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Step-by-step explanation:

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strojnjashka [21]

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3 years ago

Read 2 more answers