Question

If h(x)=x²-5x+7, find the value of h(2), and h(-5)

Answer 1

Answer:

h(2) = $2^{2}$-5(2)+7 = 1

h(-5) = $(-5)^{2}$-5(-5)+7 = 7

Step-by-step explanation:

Answer 2

H(2)= (2)^2 -5(2)+7
2^2 is 4
-5x2 is -10
+7
So 4-10+7
=1
h(2)=1

h(-5)=(-5)^2 -5(-5)+7
-5^2 is 25
-5x-5 is 25
+7
So h(-5)=57